I'm working on exercise 30, 5.2, page 587, find the exact value for the expression under the given conditions. cos(a-B);  sin a = 2/3 for a in QII and cos B = -1/4 for B in QIII.  I'm confused how to do the steps for this one, I think it is just how its asking, but I need help understanding what I am suppose to end up with?

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A:

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A: Solve:

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A: Let's find.

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Q: the answer came out to be arccos(-1/-10)/1 Could you explain this to me?

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Q: Use the addition formulas for tangent to simplify the expression. [tan(e + 77)][tan(0 – 77)] + 1

A: Explanation of the solution is given below...