ii)Identify the limiting reactant. [R.A.M: Al = 27, H = 1, S = 32, O = 16] iii) Calculate the theoretical yield of the hydrogen gas formed in terms of:

2 g of aluminium metal is mixed with 11.5 g of sulphuric acid,
H₂SO₄ to form aluminium sulphate and hydrogen gas.

i) Write the balanced chemical equation for the reaction.
ii)Identify the limiting reactant.
[R.A.M: Al = 27, H = 1, S = 32, O = 16]
iii) Calculate the theoretical yield of the hydrogen gas formed in terms
of:
i. mass in grams
ii. number of molecules
[Avogadro’s number: 6.022 x 10 ²³]
iv)Calculate the theoretical yield (mass in grams) of the
aluminium sulphate produced.
v)How many grams of the excess reactant remains after the
reaction is completed?
vi) What is the actual yield obtained for aluminium sulphate if
the percentage yield is 98.12%?