(II) Figure 4–53 shows a block (mass ma) on a smooth hori- zontal surface, connected by a thin cord that passes over a pulley to a second block (mB), which hangs vertically. (a) Draw a free-body diagram for each block, showing the force of gravity on each, the force (tension) exerted by the cord, and any normal force. (b) Apply Newton's second law to find formulas for the acceleration of the system and for the tension in the cord. Ignore friction and the masses of the pulley and cord. FIGURE 4–53 Problems 32 and 33. mB Mass ma rests on a smooth horizontal surface; mâ hangs vertically.

(c) The Thrust SSC car raised the world land speed record in 1997. The mass of the car was 1.0 x 10 kg. A 12 s run by the car may be considered in two stages of constant acceleration. Stage one was from O to 4.0 s and stage two 4.0 s to 12 s. (i) In stage one the car accelerates from rest to 44 m s in 4.0 s. Calculate the acceleration produced and the force required to accelerate the car. (ii) In stage two the car continued to accelerate so that it reached 280 m s- in a further 8.0 s. Calculate the acceleration of the car during stage two. (iii) Calculate the distance travelled by the car from rest to reach a speed of 280 ms.

1. Two blocks are connected by a massless rope as shown below. The mass of the block on the table is m₁ and the hanging mass is m₂. The table and the pulley are frictionless. a₁ y m₁ X 3 Subpart 1: Draw FBDs In your notebook, draw free body diagrams for m, and m₂ using the template as shown below. The forces acting on the system are weights of the blocks, m₁g, and mêg, the tension in the string T and the normal reaction N₁ of the table on m₁. m m₂ Subpart 2: Set up Newton's Second Law Equations a2 m₂

A 10 kg mass is pulled along a frictionless horizontal surface by a 20 Nt force that acts at 60° with respect to the horizontal. Determine: (a) The weight of the mass; (b) The mass' acceleration, ax; (c) The mass' final velocity if Vox = 0 and the force acts for 5 seconds, (d) The mass' final position, Xf, if Xo = 0.