MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- A statistics practitioner took a random sample of 57 observations from a population whose standard deviation is 25 and computed the sample mean to be 103. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 95% confidence, changing the population standard deviation to 58; Confidence Interval = C. Estimate the population mean with 95% confidence, changing the population standard deviation to 7; Confidence Interval =arrow_forwardIn the population of senior students at Shermer High School, the proportion who plan to attend college is 0.64. In a random sample of 100 students from this population, the proportion who plan to attend college is 0.75. We would call the value 0.64 a P-value. z-score. parameter statistic significance level.arrow_forwardWe provide a sample mean, sample size, sample standard deviation, and confidence level. a. use the one-mean t-interval procedure to find a confidence interval for the mean of the population from which the sample was drawn. b. obtain the margin of error by taking half the length of the confidence interval. c. obtain the margin of error by using the formula tα/2•s/n. x = 55, n = 16, s = 5, confidence level = 99%arrow_forward
- Use the study below for Part A, Part B, and Part C. A soft drink company surveys 500 shoppers and finds that 61% of shoppers prefer diet soda to regular soda. Part A: With a confidence level of 90%, what is the margin of error? Show your work and round to the nearest hundredth.Part B: If the sample size would increase to 1,000 respondents while keeping the rest of the variables the same, what would happen to the margin of error?Part C: Support your answer to Part B by finding the margin of error if 1,000 shoppers were surveyed while keeping the rest of the variables the same. Show yourarrow_forwardyou measure the weights of a random sample of twenty-five people. The sample mean is 60 kg. Suppose that the mean weights of people follow a normal distribution with an unknown mean and standard deviation of 5 kg. You compute a 95% confidence interval for μ. The 95% confidence interval for μ is?arrow_forwardConsider a sample data with x=25 and s=2. Compute a chebyshev’s interval for which at least 89% of the data will lie?arrow_forward
- Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.arrow_forwardA statistics practitioner took a random sample of 54 observations from a population whose standard deviation is 29 and computed the sample mean to be 98. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 95% confidence, changing the population standard deviation to 43; Confidence Interval = C. Estimate the population mean with 95% confidence, changing the population standard deviation to 10; Confidence Interval =arrow_forwardUse the information provided to find the minimum sample size required to estimate an unknown parameter Mean(u). How many students should be randomly selected to estimate the average weekly earnings of students at a university? We want 80% confidence that the sample mean is within $ 3 of the population mean and the population standard deviation is known to be $ 57. Select one: a. 978 b. 362 c. 1388 d. 594 e. 2397arrow_forward
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