**Dilution Problem Example**When you dilute 35.0 mL of 1.00 M hydrochloric acid to a total volume of 800 mL, you can find the molar concentration of the dilute acid using the formula for dilution:M₁V₁ = M₂V₂In this equation:- M₁ is the initial concentration (1.00 M),- V₁ is the initial volume (35.0 mL),- M₂ is the final concentration (what we want to find),- V₂ is the final volume (800 mL).**Calculation:**1.00 M * 35.0 mL = M₂ * 800 mLSolve for M₂:M₂ = (1.00 M * 35.0 mL) / 800 mLMolar concentration = M₂ M**Note:** - Ensure all volume units are consistent when using the dilution formula.- The answer for M₂ should be simplified and expressed in terms of molarity (M).**Source:**Cengage Learning | Cengage Technical Support

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If you dilute 35.0 mL of 1.00 M hydrochloric acid to 800. mL, what is the molar concentration of the dilute acid? Molar concentration = M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Dilution Problem Example**

When you dilute 35.0 mL of 1.00 M hydrochloric acid to a total volume of 800 mL, you can find the molar concentration of the dilute acid using the formula for dilution:

M₁V₁ = M₂V₂

In this equation:
- M₁ is the initial concentration (1.00 M),
- V₁ is the initial volume (35.0 mL),
- M₂ is the final concentration (what we want to find),
- V₂ is the final volume (800 mL).

**Calculation:**

1.00 M * 35.0 mL = M₂ * 800 mL

Solve for M₂:

M₂ = (1.00 M * 35.0 mL) / 800 mL

Molar concentration = M₂ M

**Note:**
- Ensure all volume units are consistent when using the dilution formula.
- The answer for M₂ should be simplified and expressed in terms of molarity (M).

**Source:**
Cengage Learning | Cengage Technical Support

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