Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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**Dilution Problem Example** When you dilute 35.0 mL of 1.00 M hydrochloric acid to a total volume of 800 mL, you can find the molar concentration of the dilute acid using the formula for dilution: M₁V₁ = M₂V₂ In this equation: - M₁ is the initial concentration (1.00 M), - V₁ is the initial volume (35.0 mL), - M₂ is the final concentration (what we want to find), - V₂ is the final volume (800 mL). **Calculation:** 1.00 M * 35.0 mL = M₂ * 800 mL Solve for M₂: M₂ = (1.00 M * 35.0 mL) / 800 mL Molar concentration = M₂ M **Note:** - Ensure all volume units are consistent when using the dilution formula. - The answer for M₂ should be simplified and expressed in terms of molarity (M). **Source:** Cengage Learning | Cengage Technical Support
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Transcribed Image Text:**Dilution Problem Example** When you dilute 35.0 mL of 1.00 M hydrochloric acid to a total volume of 800 mL, you can find the molar concentration of the dilute acid using the formula for dilution: M₁V₁ = M₂V₂ In this equation: - M₁ is the initial concentration (1.00 M), - V₁ is the initial volume (35.0 mL), - M₂ is the final concentration (what we want to find), - V₂ is the final volume (800 mL). **Calculation:** 1.00 M * 35.0 mL = M₂ * 800 mL Solve for M₂: M₂ = (1.00 M * 35.0 mL) / 800 mL Molar concentration = M₂ M **Note:** - Ensure all volume units are consistent when using the dilution formula. - The answer for M₂ should be simplified and expressed in terms of molarity (M). **Source:** Cengage Learning | Cengage Technical Support
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