Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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**Problem Statement:**

If \( x - 2 \) is a factor of \( x^4 - x^3 - mx^2 - 4 \), find the value of \( m \). Show all work to receive credit for your answer.

---

**Solution Details:**

When a polynomial \( f(x) \) has \( x - a \) as a factor, it means that \( f(a) = 0 \). For this problem, set \( a = 2 \) since \( x - 2 \) is the given factor.

1. **Substitute 2 into the polynomial:**

   \[
   f(x) = x^4 - x^3 - mx^2 - 4
   \]

   \[
   f(2) = 2^4 - 2^3 - m(2^2) - 4
   \]

2. **Calculate each term:**

   \[
   2^4 = 16, \quad 2^3 = 8, \quad 2^2 = 4
   \]

3. **Substitute these values back into the equation:**

   \[
   f(2) = 16 - 8 - 4m - 4
   \]

4. **Simplify the expression:**

   \[
   f(2) = 16 - 8 - 4m - 4 = 4 - 4m
   \]

5. **Set the equation equal to zero (because \( f(2) = 0 \)):**

   \[
   4 - 4m = 0
   \]

6. **Solve for \( m \):**

   \[
   4 = 4m
   \]

   \[
   m = 1
   \]

Therefore, the value of \( m \) is \( 1 \).
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Transcribed Image Text:**Problem Statement:** If \( x - 2 \) is a factor of \( x^4 - x^3 - mx^2 - 4 \), find the value of \( m \). Show all work to receive credit for your answer. --- **Solution Details:** When a polynomial \( f(x) \) has \( x - a \) as a factor, it means that \( f(a) = 0 \). For this problem, set \( a = 2 \) since \( x - 2 \) is the given factor. 1. **Substitute 2 into the polynomial:** \[ f(x) = x^4 - x^3 - mx^2 - 4 \] \[ f(2) = 2^4 - 2^3 - m(2^2) - 4 \] 2. **Calculate each term:** \[ 2^4 = 16, \quad 2^3 = 8, \quad 2^2 = 4 \] 3. **Substitute these values back into the equation:** \[ f(2) = 16 - 8 - 4m - 4 \] 4. **Simplify the expression:** \[ f(2) = 16 - 8 - 4m - 4 = 4 - 4m \] 5. **Set the equation equal to zero (because \( f(2) = 0 \)):** \[ 4 - 4m = 0 \] 6. **Solve for \( m \):** \[ 4 = 4m \] \[ m = 1 \] Therefore, the value of \( m \) is \( 1 \).
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