A trucking company determined that the distance traveled per truck per year is normally distributed, with a mean of 80 thousand miles and a standard deviation of 10 thousand miles. Compabelow.(...)The percentage of trucks that can be expected to travel either less than 60 or more than 95 thousand miles in a year is 8.96 %.(Round to two decimal places as needed.).c. How many miles will be traveled by at least 85% of the trucks?The number of miles that will be traveled by at least 85% of the trucks is 69636 miles.(Round to the nearest mile as needed.)d. What are your answers to parts (a) through (c) if the standard deviation is 8 thousand miles?If the standard deviation is 8 thousand miles, the proportion of trucks that can be expected to travel between 66 and 80 thousand miles in a year is(Round to four decimal places as needed.)If the standard deviation is 8 thousand miles, the percentage of trucks that can be expected to travel either less than 60 or more than 95 thousand miles in a year is %.(Round to two decimal places as needed.)miles.If the standard deviation is 8 thousand miles, the number of miles that will be traveled by at least 85% of the trucks is(Round to the nearest mile as needed.)Help me solve thisView an exampleGet more help.83°FJessType here to search& Given a normal distribution with μ = 100 and o= 10, complete parts (a) through (d).Click here to view page 1 of the cumulative standardized normal distribution table.Click here to view page 2 of the cumulative standardized normal distribution table....(Round to four decimal places as needed.)b. What is the probability that X

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A trucking company determined that the distance traveled per truck per year is normally distributed, with a mean of 80 thousand miles and a standard deviation of 10 thousand miles. Compabelow.(...)The percentage of trucks that can be expected to travel either less than 60 or more than 95 thousand miles in a year is 8.96 %.(Round to two decimal places as needed.).c. How many miles will be traveled by at least 85% of the trucks?The number of miles that will be traveled by at least 85% of the trucks is 69636 miles.(Round to the nearest mile as needed.)d. What are your answers to parts (a) through (c) if the standard deviation is 8 thousand miles?If the standard deviation is 8 thousand miles, the proportion of trucks that can be expected to travel between 66 and 80 thousand miles in a year is(Round to four decimal places as needed.)If the standard deviation is 8 thousand miles, the percentage of trucks that can be expected to travel either less than 60 or more than 95 thousand miles in a year is %.(Round to two decimal places as needed.)miles.If the standard deviation is 8 thousand miles, the number of miles that will be traveled by at least 85% of the trucks is(Round to the nearest mile as needed.)Help me solve thisView an exampleGet more help.83°FJessType here to search& Given a normal distribution with μ = 100 and o= 10, complete parts (a) through (d).Click here to view page 1 of the cumulative standardized normal distribution table.Click here to view page 2 of the cumulative standardized normal distribution table....(Round to four decimal places as needed.)b. What is the probability that X < 75?The probability that X <75 is 0.0062.(Round to four decimal places as needed.)c. What is the probability that X<95 or X > 105?The probability that X < 95 or X> 105 is 0.6170(Round to four decimal places as needed.)d. 99% of the values are between what two X-values (symmetrically distributed around the mean)?99% of the values are greater than and less than(Round to two decima' ces as needed.)View instructor tip Help me solve thisGet more help -Type here to search

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