If the specific volume is 0.00045 m³/kg and volume is 0.9 liters. Find the (a) Density (b) Mass, (c) Weight density, and (d) Relative density of the liquid. SOLUTION: (i) Density (in kg/m³) = (ii) Mass of liquid (in gm) = (iii) Weight Density (in N/m³) = %3D (iv) Relative density =

For a liquid with the contact angle of 53.6 degrees and surface tension of 0.075 N/m, capillary rise is 2.50 m. What is the expected capillary rise in meters if the liquid is replaced with another with a contact angle of 12.7 degrees and a similar surface tension? (answer should be accurate to 2 decimal places) Answer: