If the reaction temperature is too low, little reaction occurs and only a small amount of product is produced (little formation of B) If the reaction temperature is too high, most of primary product B reacts to form a lower-value secondary product (too much of B reacts to form C). So there is a temperature between these limits that maximizes the profitability of this reactor Consider the following data for the cost and values of A, B, and C Cost and value: V-$0.15/mol (cost of A in feed) V=$0.10/mol (value of A in product) V-$0.50/mol (value of B in product) V=$0.20/mol (value of C in product) A Use excel for the following calculation a. Select an arbitrary reactor temperature b. Use mole balance equations obtained in previous slides to calculate for CA, CB, and Cc Calculate an objective function (Ø has a unit of $/s) as c. Product value Feed Cost 0=EFCV-FCAOVAF which is Product value Feed cost Ø =FCV+FCBVB+FCcVct FCao VAF d. Repeat the calculation using a different temperature

If 5.9 kg of CO, are produced during a combustion reaction, how many molecules of CO, would be produced?

The point in the phase diagram where the fusion curve, the vapor pressure curve, and the sublimation curve join is called the Question 4 options:   melting point.   critical point.   double point.   boiling point.   triple point.   A sample of an ideal gas is slowly compressed to one-half its original volume with no change in temperature. What happens to the average speed of the molecules in the sample? Question 5 options:   It doubles.   It halves.   cannot be determined without more information.   It quadruples.   It does not change.     Phase changes occur Question 6 options:   as the temperature decreases.   all of the above.   none of the above.   as the temperature remains the same.   as…

Take substantial derivative of desity equation    ro = (t^(2 / 3)) + (x ^ 2) - y at (x, y, t) = (1, 1, 1)