If the pressure in container A in the given image is 212 kPa, compute the pressure in container B. Take the density values at 20°C. B Water 18 cm Oil, 16 cm SG 0.8 22 cm Mercury 8 cm 193 kPa

If the wall in following figure is 4 m long, calculate the total force on the wall due to the oil pressure. Also determine the location of the center of pressure and show the resultant force on the wall.

2. There is a liquid having density of Np below a liquid of density p (N is an unknown constant). A piston of a rectangular cross section (width H into the page) is attached to a completely submerged sphere of density e/3 and volume 4/2H3, with a pulley attachment as shown in the figure. The piston surface has a 45° angle with respect to the horizontal direction and a 90° angle with the pulley cable. It is measured that the within the piston is atmospheric. pressure (a) Identify all the forces applied to the piston surface, and mark them on a free body diagram. Accurately indicate their points of action. (b) Evaluate N if all the forces applied to the piston surface balance. Air P/3 2H g Piston surface Np H

2. Figure 2 shows the rectangular gate AB with the width of the gate is 2.5 m. Find the resultant force and its centre of pressure vertically from the water surface to gate AB. 17 m water Figure 2 B 9.6 m 7.2 m

The flat square of side length 2 m is submerged vertically in water,  2 m below the surface as shown. Find the fluid force against the surface. Use density of water is 9810 n/m^3.

The figure below shows a container filled with a liquid of density p up to a height of 4R. The container is of unit width into the plane of the screen and AB is half a parabola with a height of kR and a base of R. Determine the magnitude and direction of the vertical component Fy of the hydrostatic force acting on the curved surface AB if k = 2, R = 0.5 m, p = 1000 kg/m³ and the gravitational acceleration g = 9.81 m/s². Note that Fy is positive if it acts upwards and is negative if it acts downwards. Geometric properties of a half-parabola are also given below. Fy= 1. [-6.7362, -6.3438 kN. 4R h ထမ 35 b Liquid Р X Half-Parabola BR KR A = 3bh 1xc=²bh³ |yxc=hb³ |yy,c=²7/531 2 h63

At what depth below the surface of the oil, relative density 0.85 will produce a pressure of 110 kN/m2. What depth of water is this equivalent to?      Depth of oil in meters   Depth of water is this equivalent to

Find the center of mass of a uniform slice of pizza with radius R and angular width \theta Express your answer in terms of the variables R and \theta .