If the mass of the flowerpot is 65 kg, calculate the tension generated in every cable for equilibrium. Assume x = 1.5 m and z = 2 m. %3D CH2m 3 m -6m. B
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- The bar ABC is supported by three identical, ideal springs. Note that the springs are always vertical because the collars to which they are attached are free to slide on the horizontal rail. Find the angle at equilibrium if W = kL. Neglect the weight of the bar.Consider the following system in static equilibrium. Force vector Facts at a distance from the pin support at point O. Draw appropriate FBD as necessary. Assume frictionless pulleys If the reaction forces at O is zero and magnitude F is 169N, a. Find F and "a". (F need not necessarily be in the 4 quadrant as shown below) b. Find reaction forces at B. 4m Im 5m 12Cable AB passes over the small ideal pulley Cwithout a change in its tension. What length of cable CD is required for static equilibrium in the position shown? What is the tension Tin cable CD? T 2.1' Answers: LCD = TCD = A 42° C eTextbook and Media B 59 lb ft Ib D
- Cable AB passes over the small ideal pulley C without a change in its tension. What length of cable CD is required for static equilibrium in the position shown? What is the tension Tin cable CD? 3.7' Answers: LCD= TCD= i i A 48° B 69 lb ft lb DCable AB passes over the small ideal pulley C without a change in its tension. What length of cable CD is required for static equilibrium in the position shown? What is the tension Tin cable CD? T A 46° D 3.6' Answers: i Tco= i B 60 lb ft lbThe mass center G of the 1470-kg rear-engine car is located as shown in the figure. Determine the normal force under each tire when the car is in equilibrium. State any assumptions. Answers: GO -1348 mm-882 mm- Normal force under each of the front tires: N₁= Normal force under each of the rear tires: N₁ = eTextbook and Media GO Tutorial F DA Z Z N N
- The 428-kg uniform beam is subjected to the three external loads shown. Compute the vertical reaction (N) at the support point O if P = 4202 N, Q = 3387 N, T = 40694 Nm, x = 1.14 m, y = 1.53 m, and z = 1.46 m and the system is in equilibrium.Positive values are to the right, up, and counterclockwise. Round off only on the final answer expressed in 3 decimal places.A The square steel plate has a mass of 1830 kg with mass center at its center G. Calculate the tension in each of the three cables with which the plate is lifted while remaining horizontal. 2940 mm C 1390 mm 1390 mm A 1390 mm 2780 mm В Answers: TA = i kN TB = i kN Tc = i kN Determine the tensions in cables AB, AC, and AD. 1.45 m 2.25 m 1.15 m 0.50 m B D 2.6 m 145 kg Answers: TAB = i N TẠC = TAD = NCable AB passes over the small ideal pulley C without a change in its tension. What length of cable CD is required for static equilibrium in the position shown? What is the tension Tin cable CD? ↑ A 43° D 3.6' Answers: LCD = i TCD i B 70 lb ft lb
- The uniform 18kg Bar OA is held in the position shown by a smooth pin at 0, and the cable AB which is in tension as shown. A 1.5 m 60° 00 B -1.2 m Which of the following is the correct expression for the expression for the Tensile force (T) acting at point A Select one: fthese optionsThe mass center G of the 1540-kg rear-engine car is located as shown in the figure. Determine the normal force under each tire when the car is in equilibrium. State any assumptions. Answers: GO 1283 mm-871 mm Normal force under each of the front tires: Nf= Normal force under each of the rear tires: N₁ = i 3054 i 4499 ! N N97 lll i docs.google.com/forms/d/e, o when you upload files and submit this form. Not adyan.rashid.etcn3@student.atu.edu.iq? Switch account Q/ The mass center G of the 1400-kg rear- engine car is located as shown in the figure. Determine the normal force under each tire when the car is in equilibrium. State any assumptions. 1386 mm - 964 mm Nf= 1500, Nr= 2500 Nf= 2200, Nr= 4050 Nf= 2800, Nr= 4500 None of ablove Nf= 2820, Nr= 4050 Upload the solve