If the energy released by an electron making a transition from one hydrogen atom orbit to another is 4.57 ✕ 10−19 J, what is the wavelength (in nm) of the photon?

Electrically excited mercury atoms have particularly strong emission of 4.9 eV photons, corresponding to a transition of one of the atom’s electrons from a higher energy state to a lower. Mercury vapor absorbs light of this wavelength as well; the energy of the photon moves an electron from the lower state to the higher.It’s also possible to produce an excitation through other means. If an electron with a kinetic energy of 4.9 eV strikes a mercury atom, it can transfer energy, moving an electron in the mercury atom from the lower level to the higher. The electron loses kinetic energy in the process; this is an inelastic collision. Electrons with kinetic energies lower than this transition energy undergo elastic collisions, leaving their kinetic energy unchanged.This was the idea behind the Franck-Hertz experiment, a classic experiment of early-20th-century physics. The basic setup is illustrated in Figure P28.88a. A tube is filled with mercury vapor. A heated electrode emits…

An electron in a Hydrogen atom is in energy level n=5 and drops down into the n=2 level. What is the wavelength of the photon that is emitted in units of nm.

A hydrogen atom (mass= 1.672 x 10-27 kg) quantum jumps from the fourth excited state to the first excited state by emitting a photon. What is the kinetic energy (J) of the recoiling atom? 4.81 x 10-27 O 4.31 x 10-28 O 1.14 x 10-28 O 5.56 x 10-28 O 3.17 x 10-28 O 3.56 x 10-28 O 6.05 x 10-28 O 2.52 x 10-28 06.97 x 10.28 O 9.11 × 10-28