If the dew point of air (35°C and 1 atm) is 20 °C, what is the RH under that temperature and pressure (35°C and 1 atm)?

A helium-filled balloon has volume 3.8_m³, temperature 25.4°C, and pressure 1 atm while at sea level. If the balloon rises to 27000 ft, where the temperature is 3.5°C and the pressure is about 1/3 of its sea-level value, then find the new volume of the balloon. 10.56.m3 20.65_m3 18.71 m3 19.31 m3 А. D. 7.678 m3 20.74 m3 В. Е. С. F.

The following data are given for the pressure and temperature variation in air as a function of elevation: Elevation in [m] 0. Temperature in [°C]_pressure [atm] 28 1. 1000. 25 0.796 2000. 19 0.6314 3000. 12 0.4982 4000. 3 0.3905 5000. -1 0.3043 6000. 11 0.2356 You want to check if these measurements are correct. You are going to use a balloon and rise in the corresponding altitudes. If the balloon weighs 1000kg (all included, weight of yourself, equipment, inflated part etc) calculate the volume of inflated part of the balloon, so that the initial acceleration is 15m/s?. Assume that the balloon is a sphere and neglect the deflated part of the balloon as far as volume is concerned. Can you verify all measurements with this volume of the balloon? What kind of adjustments do you need to make in order to complete your mission?

The number density of gas atoms at a certain location in the space above our planet is about 0.75 × 1011 m-3, and the pressure is 2.65 × 10-10 Pa in this region. What is the temperature in this region, in degrees Celsius?

A hot air balloon uses the principle of buoyancy to create lift. By making the air inside the balloon less dense then the surrounding air, the balloon is able to lift objects many times its own weight. A large hot air balloon has a maximum balloon volume of 2090 m3. a.  If the air temperature in the balloon is 54 °C, how much additional mass, in kilograms, can the balloon lift? Assume the molar mass of air is 28.97 g/mol, the air density is 1.20 kg/m3, and the air pressure is 1 atm.

When the coefficient of linear expansion, a, and the temperature change, T-T, are large, a length L, of a solid substance expands in length to a(T, -T₂) L₁ = L₁e O L=L[1 + a(Tƒ– T;)]. ○ Ly=al (Ty-T). O L=L[1 + In(a(T₁-T))]. a(T, I₂ = ₁₂₁[ 1 + ª²(²₁-7)].

In a murder investigation, the temperature of the corpse was 32.5°C at 1:30 p.m. and 30.6°C an hour later. Normal body temperature is 37.0°C, and the ambient temperature was 20.0°C. How long ago (in minutes before 1:30 p.m.) did the murder take place? (Round your answer to the nearest minute.)