If the cart starts from rest, what will be its velocity after the impulse ignoring friction? If you wanted to double this final velocity, and at the same time the force would be exerted only for half of this time, so 1.5 seconds, how big force would be needed assuming the force is again constant?

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If the cart starts from rest, what will be its velocity after the impulse ignoring friction? If you wanted to double this final velocity, and at the same time the force would be exerted only for half of this time, so 1.5 seconds, how big force would be needed assuming the force is again constant?

. A constant force of 50 N is acting on a 2.5 kg cart for the total of three seconds
(as shown on the graph below).
F[N]
50
1.0
4.0
t [s]
Transcribed Image Text:. A constant force of 50 N is acting on a 2.5 kg cart for the total of three seconds (as shown on the graph below). F[N] 50 1.0 4.0 t [s]
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