College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Question
mA, I3 = If R2 = R3, then what are the values of I2 and I3? I½ = IFR +R3 and the ratio of R2/ R3 is 1/5, then what are the values of I2 and I3? Please show your work. I2 = mA, 3= mA If R2 = 100 2, and R3 = 500 2, then what is the equivalent resistance of R2 and R3 in the circuit? R23 = Ω. If R1 = 200 2, then what is the equivalent resistance of R1, R2 and R3 in the circuit in Figure 2? R123 = Ω. EM-5P.2 November 28, 2017
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Transcribed Image Text:mA, I3 = If R2 = R3, then what are the values of I2 and I3? I½ = IFR +R3 and the ratio of R2/ R3 is 1/5, then what are the values of I2 and I3? Please show your work. I2 = mA, 3= mA If R2 = 100 2, and R3 = 500 2, then what is the equivalent resistance of R2 and R3 in the circuit? R23 = Ω. If R1 = 200 2, then what is the equivalent resistance of R1, R2 and R3 in the circuit in Figure 2? R123 = Ω. EM-5P.2 November 28, 2017
Pre-lab EM-5 Ohm's Law and Kirchhoff's Rules Ohm's Law: The resistance R of a device can be determined by either directly measuring the resistance using an ohmmeter, or by measuring the current I through it and the voltage V across it, and then calculating R using Ohm's Law V R 3= (1) If the voltage across a resistor is 10V, and the current passing through it is 2.5 mA. What is the resistance of the resistor? R= Ω. Kirchhoff's Loop Rule: Around any closed circuit loop, the sum of the potential drops equals the sum of the potential rises. Two resistors are connected in series with a 10V battery as shown in Figure 1. If the voltage drop across R1 is V = 3.5 V, what should be the potential drop V2 across R2? R, R, 10V V2 = V Figure 1 Kirchhoff's Junction Rule: The sum of all currents entering any junction in a circuit is equal to the sum of the currents leaving that junction. Three resistors are connected with a power supply as shown in figure 2. Resistors R2 and R3 are connected (circle one) I, R, in series. in parallel. V, R, 2 1, R, Resistor R1 is connected with R2 and R3 (circle one) in series. in parallel. Figure 2 If the current passing through resistor R1 is 6.00 mA, then what is the sum of the current passing through Ra and R3? I2 + I3 = mA. EM-5P.1 November 28, 2017
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Transcribed Image Text:Pre-lab EM-5 Ohm's Law and Kirchhoff's Rules Ohm's Law: The resistance R of a device can be determined by either directly measuring the resistance using an ohmmeter, or by measuring the current I through it and the voltage V across it, and then calculating R using Ohm's Law V R 3= (1) If the voltage across a resistor is 10V, and the current passing through it is 2.5 mA. What is the resistance of the resistor? R= Ω. Kirchhoff's Loop Rule: Around any closed circuit loop, the sum of the potential drops equals the sum of the potential rises. Two resistors are connected in series with a 10V battery as shown in Figure 1. If the voltage drop across R1 is V = 3.5 V, what should be the potential drop V2 across R2? R, R, 10V V2 = V Figure 1 Kirchhoff's Junction Rule: The sum of all currents entering any junction in a circuit is equal to the sum of the currents leaving that junction. Three resistors are connected with a power supply as shown in figure 2. Resistors R2 and R3 are connected (circle one) I, R, in series. in parallel. V, R, 2 1, R, Resistor R1 is connected with R2 and R3 (circle one) in series. in parallel. Figure 2 If the current passing through resistor R1 is 6.00 mA, then what is the sum of the current passing through Ra and R3? I2 + I3 = mA. EM-5P.1 November 28, 2017
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