If np 25 and nq 25, estimate P(fewer than 5) with n= 14 and p 0.5 by using the normal distribution as an approximation to the binomial distribution; if np< 5 orng <5, then state that the normal approximation is not suitable......Select the correct choice below and, if necessary, fill in the answer box to complete your choice.O A. P(fewer than 5)=|(Round to four decimal places as needed.)O B. The normal approximation is not suitable.

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Answered: If np 25 and nq 25, estimate P(fewer…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean amount of time it takes a kidney stone to pass is 12 days and the standard deviation is 5 days. Suppose that one individual is randomly chosen. Let X = time to pass the kidney stone. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X - N( 12 5 or or b. Find the probability that a randomly selected person with a kidney stone will take longer than 16 days to pass it. Hint: c. Find the minimum number for the upper quarter of the time to pass a kidney stone. days.
Assume that a procedure yields a binomial distribution with n 1143 trials and the probability of success for one trial is p = 0.48. Find the mean for this binomial distribution. (Round answer to one decimal place.) Find the standard deviation for this distribution. (Round answer to two decimal places.) Use the range rule of thumb to find the minimum usual value u-20 and the maximum usual value p+2o. Enter answer as an interval using square-brackets only with whole numbers. usual values =
he population mean and standard deviation are given below. Find the required probability and determine whether the given sample mean would be considered unusual. For a sample of n=65, find the probability of a sample mean being greater than 217 if μ=216 and σ=3.5. For a sample of n=65, the probability of a sample mean being greater than 217 if μ=216 and σ=3.5 is nothing. (Round to four decimal places as needed.) Would the given sample mean be considered unusual? The sample mean ▼ would not would be considered unusual because it ▼ does not lie lies within the range of a usual event, namely within ▼ 1 standard deviation 2 standard deviations 3 standard deviations of the mean of the sample means.
The population mean and standard deviation are given below. Find the indicated probability and determine whether a sample mean in the given range below would be considered unusual. If convenient, use technology to find the probability. For a sample of n 38, find the probability of a sample mean being less than 12,750 or greater than 12,753 when u = 12,750 and o = 1.8. For the given sample, the probability of a sample mean being less than 12,750 or greater than 12,753 is. (Round to four decimal places as needed.) Would the given sample mean be considered unusual? O A. The sample mean would not be considered unusual because there is a probability greater than 0.05 of the sample mean being within this range. O B. The sample mean would be considered unusual because there is a probability greater than 0.05 of the sample mean being within this range. OC. The sample mean would not be considered unusual because there is a probability less than 0.05 of the sample mean being within this range. O…
Explain how to decide when a normal distribution can be used to approximate a binomial distribution. Choose the correct answver below O A. If np 0 and nq > 0, the normal distribution can be used. O C. If np 5 and nq 5, the normal distribution can be used. O D. If np 2 5 and nq 5, the normal distribution can be used. Click to select your answer.
I need help with b and c
Below, n is the sample size, p is the population proportion and p is the sample proportion. Use the Central Limit Theorem and the TI-84 Plus calculator to fin the probability. Round the answers to at least four decimal places. n=100 p=0.18 P(0.14
If np 25 and ng 2 5, estimate P(at least 4) with n= 13 and p = 0.4 by using the normal distribution as an approximation to the binomial distribution; if np <5 or ng < 5, then state that the normal approximation is not suitable. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. P(at least 4) = (Round to three decimal places as needed.) O B. The normal distribution cannot be used.
ne Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 42 couples. Complete parts (a) through (c) below. nents 1 of nts a. Find the mean and the standard deviation for the numbers of girls in groups of 42 births. 1 of The value of the mean is u = (Type an integer or a decimal. Do not round.) ok 1 of The value of the standard deviation is o = (Round to one decimal place as needed.) nch 1 of 1 b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high. Values of girls or fewer are significantly low. 1 of 2 (Round to one decimal place as needed.) er Contents Values of girls or greater are significantly high. 1 of 2 for Success (Round to one decimal place as needed.)…
For binomial distribution, the mean is 4 and n = 8. what is π for this distribution?
Suppose X is binomially distributed with n = 1000 and p = .7. Find the mean and the standard deviation of X. ?x = _______ and ?x =
* 00 R If np > 5 and ng 2 5, estimate P(more than 9) with n = 14 and p = 0.7 by using the normal distribution as an approximation to the binomial distribution; if np < 5 or ng < 5 then state the normal approximation is not suitable State the correct choice below and, if necessary, fill in the answer box to complete your choice. a. P(more than 9) = [ Select] %3D b. The normal distribution cannot be used. [Select] < Previous Next NOV 1 23 MacBook Air 000 DD F7 000 F3 F4 F5 F8 $ 4 V 9. 6.

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