If n=400 and ˆpp^ (p-hat) =0.36, find the margin of error at a 90% confidence level

If n=150 and ˆpp^ (p-hat) = 0.6, construct a 98% Confidence Interval.In order to use technology, you need to compute the number of successes:x = n*pp^Give your answers to three decimals.< p <

According to statistics released by CNBC, the number of vehicles that are not insured is staggering. CNBC's sample results indicate that 44 out of 80 vehicles were uninsured. Give a 95% confidence interval for the population proportion of the form p^ ± E where p^ is the point estimator of the proportion and E is the margin of error. Select one: a. The interval is 0.450 ± 0.109. b. The interval is 0.550 ± 0.143. c. The interval is 0.450 ± 0.091. d. The interval is 0.550 ± 0.091. e. The interval is 0.550 ± 0.109.

A marketing research company is estimating which of two soft drinks college students prefer. A random sample of 110 college students produced the following 95% confidence interval for the proportion of college students who prefer drink A: (0.228, 0.603). Identify the point estimate (p^p^) for estimating the true proportion of college students who prefer that drink.  Round to the nearest thousandth.

If n = 560 and ˆpp^ (p-hat) = 0.5, construct a 95% confidence interval.Give your answers to three decimals < p <

Express the confidence interval (25.4%,42.8%) in the form of p^±ME.

If n = 300 and ˆpp^ (p-hat) = 0.95, construct a 99% confidence interval.Give your answers to three decimals <p<

I have been struggling to solve this problem but I could not figure out what formula or any kind of equations that will help me solve the problem (If n=470 and ˆpp^ (p-hat) =0.83, find the margin of error at a 95% confidence level).

If n=420 and ˆpp^ (p-hat) =0.19, find the margin of error at a 95% confidence level

An excess of high values for the cases distributed on a graph results in a positive skew in the data?