If (n + 1)(n + 2)an+1x" - nan-1x" = 0, n=1 show that for k = 1, 2, 3, ..., we have 1.3.5... (2k - 1) ao, 2k+1 k! a1. (2k + 2)! a2k a2k+1 = (2k + 1)!

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Q: 2. Show that following statements are correct: i. 4n+100=0(n) iii. n³ + O(n²) v. n! = O(n) vii. 3n3…

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Q: 9. If an+1 = 2an + 2 and ao = 4, then an = O 3(2)n + 1 6(2)n-2 O 2n + 3 O none of these

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Q: e)      a(n)= (n+1)a(n-1) a(0)=2     a1= (2+1)     a2= (2+1)+1    a3= (2+1)+1)+1    a(n)= 2(n+1)!…

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A: Introduction: If a number a is divided by b, then there must exist an integer k such that, b=ak.

Q: (b) Verify that 17(s +1) (s² – 2s – 3)(s2+2s +2) s+5 (s – 3) (s2 +2s +2)

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