If Kv = 0.0147, I+ 2407 WLV Find the roots for Wev of, Kv. +w₂² × 0.003
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- A 22-k resistor and a 0.02-F capacitor are connected in series to a 5-V source. How long will it take the capacitor to charge to 3.4 V Select one: a. 0.501 ms b. 0.66 ms c. 0.44 ms d. 0.70 msIn the figure: R1 = 27.3 Q, R2 = 93.1 Q and R3 = 1571.12 Q, then determine the value of the source current Is. 12 13 RT R1 R2 R3 E 1.33 0.98 1.44 1.73 1.15In the circuit below, Find the voltage across the inductor at time t = 0.000909 s. The values are V1 = 146V, R = 4.4 ohms, L =0.02 henries
- Find current I, in the circuit of Figure Q2(b). j6Q -j42 10Ω I. j12 V 12 03 10280° A Figure Q2(b)An R-C series circuit has a supply voltage of 100 V. The resistance is 200 ohms and the capacitance is 0.0001 Farad. Solve for the current "i" at any time "t". Solve for the charge "q" at any time "t".A 1-H inductor is connected in series with a 6-ohm resistor. If the connection is energized from a 9-V DC source, determine the current (in amperes) through the circuit for a long time. The initial current is 100 mA. Express your answers accurate to four decimal places. No need to put the units.
- An inductor of 230 milli Henry, a capacitor of 15 micro farad and a 200 ohm resistor are in series across a 36 V and 60 Hz voltage source. Find the total current a. 150 mA b. 0.164 A c. 0.2 A d. 170 mAPlease show your detailed solution Number 14 The current in a series inductive circuit is 7.5 A at 25 Hz. The circuit takes 425 W, and the power factor is 0.47. The resistance of the circuit is A. 7.32 ohms C. 7.98 ohms B. 7.86 ohms D. 7.56 ohms5: For the coupled circuit shown in Figure 3, find the voltage across the capacitor of -j102 reactance with Vi-1040° V and V2-10290° V? j20 50 j50 50 -j100 Figure 3
- Q5] find the current of the resistance 1892 if the value of the source is 7.4sin(100πt-44) volt HH 1mF R1 ww 18Q R4 •14Ω 3.9mF 13.100, 78.163⁰ mA O 14.100, 78.163⁰ mA O 15.100, 78.163⁰ mA 0.093H V1Find the voltage across each inductor for the given circuit using the voltage divider rule. VL1 +m= L₁=10mH Vs=100 V, 60 Hz VL2 +mm- L₂=14mH1. A purely resistive circuit the current is leading by 90° with respect to voltage. 2. A purely inductive circuit the current is lag behind the voltage by 90°. 3. A purely capacitive circuit the current is lead by 90° with respect to the voltage. 4. A capacitor element stored magnetic energy. 5. An inductor element stored electrical energy. 6. Resistor elements consume power. 7. Angle between current and voltage is called power. 8. The power factor angle for a purely resistive is zero. 9. The power factor angle for a purely inductive load is -90°. 10. The power factor of a purely capacitive is leading.