if i have a hypothetical ionic molecule... AB3 that dissolves in H20. and A3+ is 30 ppm...how do I determine the ppm of the other half of the molecule? 3(B-)

General, Organic, and Biological Chemistry
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Chapter8: Solutions
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Problem 8.10EP: A solution is made by dissolving 0.455 g of PbBr2 in 100 g of H2O at 50C. Based on the data in Table...
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if i have a hypothetical ionic molecule... AB3 that dissolves in H20. and A3+ is 30 ppm...how do I determine the ppm of the other half of the molecule? 3(B-)

ppm as I understand it is 1 gram of solute /1000 mL of solvent. But I don't understand what happens when that solute breaks into its anion and cation when solvating.

I think it is either 10 ppm since there are 3B for every A , or it is 70 ppm so that A + B = 100%

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