If h(x) = -2x2 - x + 4, find h(-2), h(-3), h(4), and h(5).

Q: If Q(x) = 7x - 1, find Q(- 9). Q(- 9) =

A:

Q: X-2-9x-1+14=0

A: Let z=x^-1We replace x^-2 by z^2 and x^-1 by z.

Q: x(x-6)=-8

A: Givenx(x-6)=-8

Q: X-2y=1;(  ,-2),(7,  )

A: The given function:

Q: 2ax - y = 3x + 4y for x

A: Simplification

Q: 5(x + 3) = -5 - 5x

A:

Q: 5(-3x-2)-(x-3)=-4(4x+5)+13

A: The given equation is

Q: If y =(3x)2 + 17 when x = -2 what is y

A: That's easy, just substitute value of x and you are done.

Q: 2(x+3)-3(x+4)=-x+18

A: Solve and find solution:

Q: y = -x - 5x + 6 and y = (x + 1)2 - 2 |

A:

Q: X -3 ar?

A: We have to divide (2x2 + 5x - 7) by (x - 3).

Q: 5x-16-3x| if x>2

A: Solution is given below:

Q: -x + y2 = 3 and x + y2 - y = 0

A: Consider the given equations as,

Q: -(4x5 - 3x3 + 5x - 2x2 + 2) - (-3x3

A: We have to simplify

Q: -2x+6x-6=4(x-3)-3

A: Here we should place variables ( in this question, the terms containing x) should place left or…

Q: is 3(x- 3x-1): =- 3x -3-4

A: Given :- 3x-1=-6

Q: y = -5x y =) 3x 3

A:

Q: If Q(x) = 6x - 1, find Q(- 7). 2 Q(- 7) =

A: The objective of the question find the the value of the function at x=-7.

Q: -2(x-4)+12(3-2x)=-8

A:

Q: 3. (x²-x+6)÷( x- 3)

A: Here we have to divide it.

Q: 2x - (x-4) = 0

A: Please refer the attached image for complete solution. THANK YOU.

Q: 3x+y=4 -x+y+5

A:

Q: -11x+5-4(x-1)=-4x-(10x-4)+4

A:

Q: 3n y = त

A:

Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.