If H is normal, then xHxH KCH. Since o(K)= o(H), then we obtain H = K, this shows that H is unique. Sylow's Third Theorem. The number of Sylow p-subgroups in G, for a given prime p, is of the form 1+kp, where k is some non-negative integer and (1 + kp) | o(G). Proof. Let M be the set of all Sylow p-subgroup of G and H be any fixed number of

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If H is normal, then xHxH
KCH.
Since o(K) = o(H), then we obtain H = K, this shows that H is unique.
Sylow's Third Theorem. The number of Sylow p-subgroups in G, for a given prime
p, is of the form 1+kp, where k is some non-negative integer and (1 + kp) | o(G).
Proof. Let M be the set of all Sylow p-subgroup of G and H be any fixed number of
Transcribed Image Text:If H is normal, then xHxH KCH. Since o(K) = o(H), then we obtain H = K, this shows that H is unique. Sylow's Third Theorem. The number of Sylow p-subgroups in G, for a given prime p, is of the form 1+kp, where k is some non-negative integer and (1 + kp) | o(G). Proof. Let M be the set of all Sylow p-subgroup of G and H be any fixed number of
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