If f(x)=(x^2+3x+4)^4 find f'(x) and f'(2)

Q: find f(x) so that f'(x)=-4e^(x)-6sinx

A: To find f(x) from f'(x) , we have to integrate f'(x) We first separate the integral

Q: f(x)=sqrt(5x^2+5x+8) f′(x)=    f'(5)=

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Q: G(x)=5x^2 ; f(x)=10x Find the anti derivatives of f

A: G(x) = 5x2f(x) = 10x

Q: Find f’’(x) of F(x)= (X^2)/(1+2x)

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Q: f(x)=9/(5x^2+4x+1)^2 find f'(x)

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Q: F''(x)=6x+4 and f'(-3)=-2 and f(-3)=-1 Find f'(x)= and find f(2)=

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Q: Find f''(x) if f(x) = e^3x^2+1.

A: calculate the second derivative for the given function

Q: Find f''(x) for f(x)=5x^2+e^(-2x).

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Q: Find the derivative of f(x) = (x-2x)2 A) f'(x) = 6x5 - 12x3+ 8x B) f'(x) = 6x5- 16x3 + 8x %3D C)…

A: Here we find the derivatives of function.

Q: find the derivative of  a. f(x)=x/x^2+(square root of 3x)^5 b. f(x)= (x-1)^3/x(x+3)^4

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Q: f(x)=(16x^3+24x^2+3x) (7x-1)/(15x^3+20x^2+5x) what is the derivatives

A: f(x)=(16x3+24x2+3x)(7x-1)(15x3+20x2+5x) To find derivative we apply product rule and quotient rule…

Q: 3. f(x)=(2x^2)(3x^2-x+7) 4. f(x)=-3(2x+7)^5   Need to find the derivative.

A: 3. Given function is Differentiating with respect to x, by using product rule of differentiation…

Q: need help finding F'(x) and f''(x) when f(x)= 5x^3-2/x^2

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Q: Assume a function such that Y = (2x410)/(6x² + 5x). Obtain the first derivative. O f'(X) = (8x³ -…

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Q: find the inverse of the function  f(x)=4x^3+8 f^-1(x)=

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Q: If f(x) = 2x^2 - 10x - 33 , what would the derivative f’(x) be?

A: Given : fx = 2x2-10x-33

Q: For the function F(x)=x^2/3+x Find F''(x)

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Q: If f(x)=7−x^2/6+x^2 find f'(x)

A: The function is given by fx = 7-x26+x2 To evaluate:The expression of f'x

Q: If f(x)=(5x^2−8)(3x+2) find f'(x) and f'(5)

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Q: If f (x)=x^5, what is f^(6) (x)?

A: The given function f(x) = x5.

Q: Find y=f(x) if f''(x)=4x^2, f'(0)=3, and f(0)=2.

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Q: find f'(x)f(x)=12x^5+9x^2/3

A: Apply the sum rule (f+g)'=f'+g'

Q: Find f'(x) if f(x)= 5sin^2(4x^2-5x+1)

A: Question- Find f'(x) if f(x)= 5sin^2(4x^2-5x+1)

Q: f'(x)=3x^2-6x-3. =3(x-1)^2-6. For what values of x is f'(x)=0?

A: f'(x)=03(x-1)2-6=03(x-1)2=6 (x-1)2=63  (x-1)2=2 (x-1)=±2