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If f is a differentiable function, find the derivative y=f(và) ƒ (√x) + √ √ f(x) 1 ○ y = ƒ (√√x) + 2 √/ F(x) 31 = ƒ1 ( 21/2 ) + 2√/131(2) f1(√x) yl= + 2√√x f1(x) 2√ √ f(x) y=f(2) + = ƒ1 ( 21√/=) + 2√/18 (2)

If f is a differentiable function, find the derivative y=f(và) ƒ (√x) + √ √ f(x) 1 ○ y = ƒ (√√x) + 2 √/ F(x) 31 = ƒ1 ( 21/2 ) + 2√/131(2) f1(√x) yl= + 2√√x f1(x) 2√ √ f(x) y=f(2) + = ƒ1 ( 21√/=) + 2√/18 (2)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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If f is a differentiable function, find the derivative y=f(và) ƒ (√x) + √ √ f(x) 1 ○ y = ƒ (√√x) + 2 √/ F(x) 31 = ƒ1 ( 21/2 ) + 2√/131(2) f1(√x) yl= + 2√√x f1(x) 2√ √ f(x) y=f(2) + = ƒ1 ( 21√/=) + 2√/18 (2)
Transcribed Image Text:If f is a differentiable function, find the derivative y=f(và) ƒ (√x) + √ √ f(x) 1 ○ y = ƒ (√√x) + 2 √/ F(x) 31 = ƒ1 ( 21/2 ) + 2√/131(2) f1(√x) yl= + 2√√x f1(x) 2√ √ f(x) y=f(2) + = ƒ1 ( 21√/=) + 2√/18 (2)
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