Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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Transcribed Image Text:If an WwXxyyZz individual is crossed to an WWXXYYZZ individual, what is the probability that the first offspring will be of WwxxyyZz genotype?
O A. 1/8
B. 3/64
C. 1/16
D. 1/64
O E. 1/32
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- 1) If the parents of the first generation are SS and ss, then the second generation (mating of first-generation) will be, (choose) a) all Ss b) 1/4 SS, 1/2 Ss, and 1/4 ss c) 1/2 Ss and 1/2 SS d) 1/2 ss and 1/2 Ss 2) In a cross of Tt x Tt, the percentage of offspring that will have the same genotype as the parents is (choose) a) 75% b) 25% c) 50% d)100%arrow_forwardUsing the following allelic series A1>A2>A3>A4, indicate what would be the phenotype of a A1A3 heterozygote? O A) A1 phenotype O B) A3 phenotype C) both A1 and A3 phenotypes D) A2 phenotypearrow_forwardExplain the following features of the Mendelian traits and fill the Punnet Squares. a)The disappearance of recessive phenotype in the F1 generation. b)The genotype of an individual expressing dominant phenotype can be differentiated by the test cross.arrow_forward
- If two individuals are crossed (RrYy x RrYy), what percentage of their offspring will display the R_yy phenotype? (the _ could be either R or r, it would not affect the phenotype).arrow_forwardCan you draw punnet square for F1 and F2 for this crossarrow_forwardFreckles is determined by a single gene and having freckles is dominant over not having freckles. If a man with freckles and a woman without freckles have a child that does not have freckles then a)the man is heterozygous for the freckles gene. b)the child is heterozygous for the freckles gene. c)the woman and man are both heterozygous for the freckles gene. d) the woman is heterozygous for the freckles genarrow_forward
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