If an elctron orbits a proton with an orbital radius of 1*10^-12 m, how fast is it moving

V 1 c²r The time dilation a distance from Earth's center is 3 = 2GM. The speed of a satellite in a stable circular orbit is v= GM due to the speed of a satellite + dilation due to gravity exactly equal the dilation experienced by a person at Earth's surface where 3 = two clocks run at the same rate? At what height above Earth's surface will the dilation 2GM? In other words, at what height will the V C² RE

The earth orbits the sun at an approximate velocity v = 30 km/s and radius r = 150*10^6 km. (a) Assuming a circular orbit for the earth, what is the approximate mass of the sun? (b) If the mass of the sun was doubled, what would the new length of a year be? Assume the Earth remains in circular orbit about the sun at its usual orbital radius. Answer in terms of current years. (Hint: you do not need to plug in the value of G.)

Calculate the force of attraction between two small object of mass 10kg and 50kg respectively which are 10cm apart. Take G as 6.67*10^-1NM^2kg^-2. If the mass of a proton is 1.67*10^-27kg and the mass of an electron is 9.11*10^-31kg, calculate the force of gravitation between {1} a proton and an electron {2} two electrons {3} two protons. Take G= 6.67*10^-11NM^2kg^-2 distance between the electrons=2*10^-2m distance between the proton and electron=5.4*10^11