If AABC having vertices A(a cos 0₁, a sin 0₁), B(a cos 02- a sin 0₂), and C(a cos 03, a sin 03) is equilateral, then prove that cos ₁+ cos 0₂ + cos 03 = sin 0, + sin 0₂2 + sin 0₂ = 0.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.5: Product-to-sum And Sum-to-product Formulas
Problem 37E
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If AABC having vertices A(a cos 0₁, a sin 0₁), B(a cos 0₂,
a sin 0₂), and C(a cos 03, a sin 03) is equilateral, then prove
that cos 0₁ + cos 0₂ + cos 03 = sin 0₁ + sin 0₂ + sin 03 = 0.
Transcribed Image Text:If AABC having vertices A(a cos 0₁, a sin 0₁), B(a cos 0₂, a sin 0₂), and C(a cos 03, a sin 03) is equilateral, then prove that cos 0₁ + cos 0₂ + cos 03 = sin 0₁ + sin 0₂ + sin 03 = 0.
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