If a solution containing 100.82 g100.82 g of mercury(II) nitrate is allowed to react completely with a solution containing 17.796 g17.796 g of sodium sulfide, how many grams of solid precipitate will form?     How many grams of the reactant in excess will remain after the reaction?

For the following reaction, 58.6 grams of potassium hydroxide are allowed to react with 37.9 grams of phosphoric acid potassium hydroxide ( aq ) + phosphoric acid ( aq ) potassium phosphate ( aq ) + water ( I ) What is the maximum amount of potassium phosphate that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams Submit Answer Try Another Version 3 item altempts remaining

Iron(II) sulfide reacts with hydrochloric acid according to the reaction FeS(s)+2HCl(aq)→FeCl2(aq)+H2S(s) A reaction mixture initially contains 0.218 mol FeS and 0.636 mol HCl. Once the reaction has reached completion, what amount (in moles) of the excess reactant is left?

A 5.30 mLmL sample of an H3PO4H3PO4 solution of unknown concentration is titrated with a 1.050×10−2 MNaOHMNaOH solution. A volume of 7.32 mLmL of the NaOHNaOH solution was required to reach the equivalence point. What is the concentration of the unknown H3PO4H3PO4 solution?         Express your answer with the appropriate units.   Value___?  Units____?