If a solution containing 58 g of mercury(II) nitrate is allowed to react completely with a solution containing 16.642 g of sodium sulfate according to the equation below: Hg(NO3)2(aq)+Na2SO4(aq)------2NaNO3(aq)+HgSO4(s)   A. How many grams of solid precipitate will be formed if the reaction has a 100% yield? B. How many grams of the excess reagent will remain after the reaction? C. If the reaction has only an 80% yield, how many grams of solid precipitate will be formed?

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Q: 1. A student adds 25.27 mL of a 0.750 M Na2SO4 solution to another solution containing 2.50 grams of…

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