
MATLAB: An Introduction with Applications
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ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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![### Understanding Geometric Distribution in Binomial Trials
If a procedure meets all of the conditions of a binomial distribution except the number of trials is not fixed, then the geometric distribution can be used. The probability of getting the first success on the \( x \)th trial is given by:
\[ P(x) = (1 - p)^{x-1} p \]
where \( p \) is the probability of success on any one trial. Subjects are randomly selected for a health survey. The probability that someone is a universal donor (with blood group O and type Rh negative blood) is 0.07.
### Problem Statement
Find the probability that the first subject to be a universal blood donor is the sixth person selected.
\[ \text{The probability is} \ \]
(Round to four decimal places as needed.)
### Steps to Solution
- Identify the given parameters:
- \( p \) (probability of success) = 0.07
- \( x \) (number of trials until the first success) = 6
- Apply the geometric distribution formula:
\[ P(x) = (1 - p)^{x-1} p \]
- Substitute the values into the formula:
\[ P(6) = (1 - 0.07)^{6-1} \times 0.07 \]
\[ P(6) = (0.93)^5 \times 0.07 \]
- Calculate the probability:
\[ P(6) \approx 0.6650 \times 0.07 \]
\[ P(6) \approx 0.0466 \]
### Final Answer
The probability is approximately 0.0466.
***Interactive Component:***
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***Graph/Diagram:***
There are no graphs or diagrams provided in the image. The content is focused entirely on the theoretical understanding and application of the geometric distribution in a binomial context.](https://content.bartleby.com/qna-images/question/4329428e-634a-426f-87a7-743e1da6a5be/1358fd8c-c298-4961-a284-3f33739df0fe/qd3mnls_thumbnail.jpeg)
Transcribed Image Text:### Understanding Geometric Distribution in Binomial Trials
If a procedure meets all of the conditions of a binomial distribution except the number of trials is not fixed, then the geometric distribution can be used. The probability of getting the first success on the \( x \)th trial is given by:
\[ P(x) = (1 - p)^{x-1} p \]
where \( p \) is the probability of success on any one trial. Subjects are randomly selected for a health survey. The probability that someone is a universal donor (with blood group O and type Rh negative blood) is 0.07.
### Problem Statement
Find the probability that the first subject to be a universal blood donor is the sixth person selected.
\[ \text{The probability is} \ \]
(Round to four decimal places as needed.)
### Steps to Solution
- Identify the given parameters:
- \( p \) (probability of success) = 0.07
- \( x \) (number of trials until the first success) = 6
- Apply the geometric distribution formula:
\[ P(x) = (1 - p)^{x-1} p \]
- Substitute the values into the formula:
\[ P(6) = (1 - 0.07)^{6-1} \times 0.07 \]
\[ P(6) = (0.93)^5 \times 0.07 \]
- Calculate the probability:
\[ P(6) \approx 0.6650 \times 0.07 \]
\[ P(6) \approx 0.0466 \]
### Final Answer
The probability is approximately 0.0466.
***Interactive Component:***
- **Enter your answer:**
You can type your answer directly into the provided answer box and click "Check Answer" to verify your solution.
***Graph/Diagram:***
There are no graphs or diagrams provided in the image. The content is focused entirely on the theoretical understanding and application of the geometric distribution in a binomial context.
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