If a molecule demonstrates paramagnetism, then: The substance can have both paired and unpaired electrons. The bond order is not a whole number. It can be determined by drawing a Lewis structure. It must be an ion. I. II. IV. O A. I, I O B. I, II, IV O C. I, II D.I only E. All of the above are correct.

If a molecule demonstrates paramagnetism, then: The substance can have both paired and unpaired electrons. The bond order is not a whole number. It can be determined by drawing a Lewis structure. It must be an ion. I. II. IV. O A. I, I O B. I, II, IV O C. I, II D.I only E. All of the above are correct.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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