Question
If a long wire carrying current is going into the page of the two loops, what force would it require? Why is the answer 0 and why is the angle 180 degrees, and not 90 degrees.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by stepSolved in 2 steps
Knowledge Booster
Similar questions
- A solenoid has length L, total number of turns N and current I. What happens to the magnitude of the magnetic held (B) inside the solenoid if the number of turns is doubled, with the length and current remaining the same? It becomes four times larger. It becomes one-fourth as large. It is unchanged. O It becomes one-half as large. O It becomes twice as large.arrow_forwardTwo coplanar and concentric circular loops of wire carry currents of I, = 5.90 A and I, = 2.30 A in opposite directions as in the figure below. Let r, = 12.0 cm and r, = 8.60 cm. (Assume the positive direction along the axis perpendicular to the faces of the loops is out of the screen (towards you) and assume the positive vertical direction is toward the top of the screen.) (a) What is the magnitude of the net magnetic field (in µT) at the center of the two loops? PT (b) What is the direction of the net magnetic field at the center of the two loops? out of the screen O into the screen O toward the top of the screen O toward the bottom of the screen (c) Let r, remain fixed at 12.0 cm and let r, be a variable. Determine the value ofr, (in cm) such that the net field at the center of the loops is zero. cmarrow_forwardA battery is connected to wires that hand vertically (gravity acts down in the diagram). Hooks at the ends of the wires hold a horizontal copper bar (the thick bar) of mass 0.6 kg and length 0.5 meters. Another apparatus (not shown) can create a uniform magnetic field in the region of space given by the dashed rectangle. The total resistance of the circuit is 1.20 Ohms and the battery supplies 24 Volts. The magnetic field can be adjusted in strength until the bar lifts off of the hooks and levitates magnetically – not moving just above the hooks as shown. a) Determine the necessary direction of the magnetic field in the dashed rectangle. b) Calculate the required magnitude of the magnetic field.arrow_forward
- A solenoid is oriented so that its axis is vertical.Viewed from above, the current flows counter-clockwise around the solenoid.(a) Would a proton moving north inside the solenoid feel a force? If so, inwhat direction? If not, why not? (b) Would a proton moving upward feel aforce? If so, in what direction? If not, why not?arrow_forward(b) Find the toroidal coil similar to that shown in Figure 2 but having a circular cross section with a = 1.2 cm, b = 2 cm and N = B is uniform throughout the inner part of the toroid. b 1000. The magnetic field Figure 2 aarrow_forwardDon't use chatgpt will upvotearrow_forward
arrow_back_ios
arrow_forward_ios