College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- An electron is a subatomic particle (m= 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +7.31 x 105 m/s to a final velocity of 1.98 x 106 m/s while traveling a distance of 0.0545 m. The electron's acceleration is due to two electric forces parallel to the x axis: F₁ = 7.52 x 10-¹7 N, and F2, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2. F₁ F₁ F₂ F₁ (a) Number i (b) Number i VO X Units Unitsarrow_forwardReview Conceptual Example 16 as background for this problem. The water skier there has a mass of 80.0 kg. Find the magnitude of the net force acting on the skier when (a) she is accelerated from rest to a speed of 11.0 m/s in 8.00 s and (b) she lets go of the tow rope and glides to a halt in 23.0 s.arrow_forwardTwo constant forces act on an object of mass m = 4.30 kg object moving in the xy plane as shown in the figure below. Force F, is 26.5 N at 35.0°, and force F, is 48.0 N at 150°. At time t = 0, the object is at the origin and has velocity (3.50î + 2.15j) m/s. 150° 35.0° (a) Express the two forces in unit-vector notation. F, - N (b) Find the total force exerted on the object. N (c) Find the object's acceleration. m/s2 Now, consider the instant t = 3.00 s. (d) Find the object's velocity. m/s (e) Find its position. (f) Find its kinetic energy from V½mv2. kJ (g) Find its kinetic energy from 2mv,2 + EF · AF. kJarrow_forward
- A ball of mass 2 kilograms is loaded into a spring gun which is pointed vertically upward. At t = 0 seconds, the spring gun exerts an upward force of 100 newtons for 1 second. Assuming a drag coefficient of 0.3 kilograms per second and drag proportional and against the velocity, give a second-order equation and initial conditions for vertical position y in meters of the ball that is initially at rest. Use g = 9.8 meters per second per second and assume the initial position is 0.arrow_forwardA bullet with a mass of 20.0 grams is fired from a gun with a 10.0 cm barrel at a velocity of 300.0 m/s. Assuming it starts from rest and accelerates uniformly, what is the magnitude of the force exerted on the bullet?arrow_forwardA 1250 kg boat is traveling at 90 km/h when its engine is shut off. The magnitude of the frictional force fk between boat and water is proportional to the speed v of the boat. Thus, fk = 80v, where v is in meters per second and fk (the magnitude of the frictional force) is in newtons. Find the time required for the boat to slow down to 45 km/h.arrow_forward
- Thank you!arrow_forwardA 1090 kg boat is traveling at 92 km/h when its engine is shut off. The magnitude of the frictional force ?→?f→k between boat and water is proportional to the speed v of the boat: fk = 85v, where v is in meters per second and fk is in newtons. Find the time required for the boat to slow to 46 km/h.arrow_forwardThe velocity of an object of mass m= 5.00 kg is giving by v(t) = (3.0m/s3)t2+ (2.00 m/s2)t. The velocity of the object at t = 0 s is equal to vo = 0 m/s. Find the force as a function of time that causes the object to move.arrow_forward
- A 0.150 kg particle moves along an x-axis according to x(t)=-13.00 + 2.00t + 4.00 t^2-3.00t^3, with x in meters and t in seconds. In unit vector notation, what is the net force acting on the particles at t=3.40 s?A) (-3.24 N)iB) (-15.4 N)iC) (-7.98 N)iD) (+3.24 N)iarrow_forwardA 12 kg meteor experiences an acceleration of 7.2 m/s*2, when falling towards the earth. a) How high above the earth's surface is the meteor? b) What force will a 30 kg meteor experience at the same altitude?arrow_forwardA 78.0 kg person falls straight down from a 1.60 m height (measured from his feet) and lands with weight distributed equally on both feet. To soften the blow, he bends his knees so that it takes 0.750s for him to stop once his feet touch the ground. (a) What average force does the floor exert on each foot while he is stopping?(b) Suppose instead that he lands stiff-legged and stops in only 0.100s. What force does the floor now exert on each foot?arrow_forward
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