Chemistry
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Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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If 860 mLs of 0.407 M K3PO4 are mixed with 746 mLs of 0.557 M Mg(NO3)2, what is the mass in grams of the resulting precipitate?
Answer with proper sig figs
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- What’s the answer in molarrow_forwardA chemist combines 53.5 mL of 0.350 M potassium bromide with 23.9 mL of 0.533 M lead nitrate. (a) How many grams of lead bromide will precipitate? (b) What is the final molarity of the K* ion? (c) What is the final molarity of the lead or bromide ion, whichever one is in excess? (а) g PbBr2 (b) M Kt (c) Мехсess ionarrow_forwardConsider the reaction of Potassium Phosphate and Nickel (II) Bromide, where 15.00 ml of 0.7000M K3PO4 is mixed with 15.00ml of 0.2000M NiBr2 (and the final volume is 30.00 ml, that is there is no change in volume upon mixing). Your answer has to include all of the following: What is the limiting reagent? What is the identity and mass of precipitate formed? What is the concentration of the alkali metal that is a spectator ion? What is the concentration of the excess phosphate?arrow_forward
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