If 60% of the population of the US need to have their vision corrected, we say that the probability that an individual chosen at random from the population needs vision correction is P(C)=.60. a. Estimate the probability that an individual chosen at random does not need vision correction. b. If 3 people are chosen at random from the population, what is the probability that all 3 need correction? c. If 3 people are chosen at random from the population, what is the probability that the second person does not need correction but the first and third do? d. If 3 people are chosen at random from the population, what is the probability that 1 out of 3 needs correction?
If 60% of the population of the US need to have their vision corrected, we say that the probability that an individual chosen at random from the population needs vision correction is P(C)=.60. a. Estimate the probability that an individual chosen at random does not need vision correction. b. If 3 people are chosen at random from the population, what is the probability that all 3 need correction? c. If 3 people are chosen at random from the population, what is the probability that the second person does not need correction but the first and third do? d. If 3 people are chosen at random from the population, what is the probability that 1 out of 3 needs correction?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Just need D
![Given:
P(C) = 0.60
(a) P(does not need vision correction)
(b)P All three
need
correction)
= (0.60) (0.60] (0.60)
0.2160
(c) P{ 1st sard need correction and 2nd
1-pcc)
=1-0.60
= 0.40
not]
=p(c) .pc c²) (pcc)
= (0-60] (0.40] (0.60)
= 0.144](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1da2b7e6-ff1f-4d03-afb3-6b710fedc971%2Fd816a203-93d9-4f3b-b3da-e450c285d39c%2Fuc2vpt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Given:
P(C) = 0.60
(a) P(does not need vision correction)
(b)P All three
need
correction)
= (0.60) (0.60] (0.60)
0.2160
(c) P{ 1st sard need correction and 2nd
1-pcc)
=1-0.60
= 0.40
not]
=p(c) .pc c²) (pcc)
= (0-60] (0.40] (0.60)
= 0.144
Transcribed Image Text:1.1.3
If 60% of the population of the US need to have their vision
corrected, we say that the probability that an individual chosen
at random from the population needs vision correction is
P(C)=.60.
a. Estimate the probability that an individual chosen at random
does not need vision correction.
b. If 3 people are chosen at random from the population, what is
the probability that all 3 need correction?
c. If 3 people are chosen at random from the population, what is
the probability that the second person does not need correction
but the first and third do?
d. If 3 people are chosen at random from the population, what is
the probability that 1 out of 3 needs correction?
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