If 6.88 grams of hydrogen is allowed to react with 6.88 grams of oxygen by the following equation and oxygen is known to be the limiting reactant, how much hydrogen is leftover after the reaction? 2 H2 (s) + O2 (g) → 2 H20 (g) molar mass of H2 = 2.02g/mol molar mass of O2 = 32.00g/mol Round your answer to the hundredths place. (Ex: 111.1111 would become 111.11) Your Answer: Answer units

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A Question 9
If 6.88 grams of hydrogen is allowed to react with 6.88 grams of oxygen by the
following equation and oxygen is known to be the limiting reactant, how much
hydrogen is leftover after the reaction?
2 H2 (s) + O2 (g) → 2 H20 (g)
molar mass of H2 = 2.02g/mol
molar mass of O2 = 32.00g/mol
Round your answer to the hundredths place. (Ex: 111.1111 would become
111.11)
Your Answer:
Answer
units
Transcribed Image Text:A Question 9 If 6.88 grams of hydrogen is allowed to react with 6.88 grams of oxygen by the following equation and oxygen is known to be the limiting reactant, how much hydrogen is leftover after the reaction? 2 H2 (s) + O2 (g) → 2 H20 (g) molar mass of H2 = 2.02g/mol molar mass of O2 = 32.00g/mol Round your answer to the hundredths place. (Ex: 111.1111 would become 111.11) Your Answer: Answer units
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