If 4.11 mol of C,H, reacts with excess O,, how many moles of CO, will be produced by the following combustion reaction? C,H +80, - 6H,0+5CO,

What do you need to do first in this problem: "If 17 g of Al reacted with 13 g 02, how many moles of A1203 are produced?" 4 Al (s) + 3 02 (g) --> 2 A1203 (s) O Write a balanced reaction Determine how many and what the given substances are and what substance is the needed one Multiply by the stoichiometric ratio Calculate the molar mass of A1203 needed to divide the grams by

Given the following equation 4Al + 3O2 ---> 2 Al2O3 a) calculate the theoretical yield of Al2O3 when 81.0 g of aluminum metal reacts with excess oxygen. b) If only 106g of Al2O3 formed, what is the % yield?

Base on the following chemical equation: NH3(g) + F2(g) ---> N2F4(g) + HF(g) 1. How many grams of N2F4 can be produced when 3.40 grams of NH3 reacts?

2.) The first step in the reaction of Alka - seltzer with mole of (NaHCO3) to produce one mole (NaCl) of Stomach acid consists of one reacting with one mole of (HCI) OF CH ₂ CO 3), and one mole Using this stoichiometry, determine the number of moles Of Carbonic acid that can be produced from 5 mol NaHCO3 and 8 mol HCl 2 Which of the two reactants limit the moles OF H₂ CO3 that can be made? 2 reactant remains after How much excess the reaction ?

The following reaction is single replacement: 2La+6HF-->2LaF3+3H2 . 100.0 g of La was reacted, how many moles of HF would be required

7

The first step in the reaction of Alka-Seltzer with stomach acid consists of one mole of sodium bicarbonate (NaHCO,) reacting with one mole of hydrochloric acid (HCI) to produce one mole of carbonic acid (H, CO,), and one mole of sodium chloride (NaCl). Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 5 mol NaHCO, and 6 mol HCl. moles of carbonic acid : mol Which of the two reactants limits the number of moles of H, CO, that can be made? O HCI O NAHCO, How much excess reactant remains after the reaction? terms of use contact us help about us privacy policy careers MacBook Air

The first step in the reaction of Alka-Seltzer with stomach acid consists of one mole of sodium bicarbonate (NaHCO, ) reacting with one mole of hydrochloric acid (HCI) to produce one mole of carbonic acid (H,CO, ), and one mole of sodium chloride (NaCl). Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 4 mol NaHCO, and 9 mol HCI. moles of carbonic acid : mol Which of the two reactants limits the number of moles of H, CO, that can be made? NAHCO, HCI How much excess reactant remains after the reaction? excess reactant : mol

When 24 mol of methanol and 15 mol of oxygen combinein the combustion reaction 2 CH3OH1l2 + 3 O21g2¡2 CO21g2 + 4 H2O1g2, what is the excess reactant and howmany moles of it remains at the end of the reaction?(a) 9 mol CH3OH1l2 (b) 10 mol CO21g2 (c) 10 mol CH3OH1l2(d) 14 mol CH3OH1l2 (e) 1 mol O21g2