If 3.82 mol of an ideal gas has a pressure of 2.99 atm and a volume of 78.23 L, what is the temperature of the sample in degrees Celsius?

An ideal gas is a hypothetical gas where the gas molecules moves randomly without any intermolecular interaction. The conditions to become a gas is ideal is standard pressure and temperature.

The fomula of an ideal gas is

$PV=nRT$

• P is pressure
• V is volume
• n is amount in mole
• R is universal gas constant
• T is temperature

Putting all the values in the above equation

$$\begin{gathered} PV=nRT \\ 2.99 atm\times 78.23 L=3.82 mol\times 0.082 L-atm\times mo{l}^{-1}{K}^{-1}\times T \\ T=\frac{2.99 atm\times 78.23 L}{3.82 mol\times 0.082 L-atm\times mo{l}^{-1}{K}^{-1}} \\ =746.73 K \\ =473.73{ }^{0}C \end{gathered}$$