If 2.00 mL of 0.0040 M NaOH are added to 50.0 mL of 0.100 M CdCl2, will a precipitate form? The ions present in solution are Na+, OH-, Cd 2+, CH-. The Only possible precipitate is: Cd(OH)2 (solubility rules). Is Qsp > Ksp for Cd(OH)2? Cd(OH) 2 (s) Ksp Cd(OH)2 = 2.50 x 10-14 EQ (M): Cd2+ (aq) + 2 OH- (aq) X mol Cd 2+ = 0.0500 L x 0.100 mol/L = 0.00500 mol [Cd2+] = 0.00500 mol/0.0520 L = 0.09615 M mol OH = 0.0020 L x 0.0040 M = 8.0 x 10-6 mol [OH-] 8.0 x 10-6 mol/0.052 L = 1.538 x 10-4 M = Qsp = [Cd 2+ ] [OH-] 2 2x = 0.09615 x (1.538 x 10-4)² = 2.27 x 10-9 NO precipitate will form Ksp = [Cd2+] [OH-]² = 2.50 x 10-14 Qsp < Ks sp

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3. Why is it proper to read the initial volume of the buret instead of trying to adjust the volume to a round number such as 0 mL? 4. Calculate the molarity of a NaOH solution if 23.25 mL of NaOH is titrated with 0.475 grams of KHP and 1.25 mL of 0.100 M HCI is required.

O SIMPLE REACTIONS Ghaya Determining the volume of base needed to titrate a given mass... A chemistry student weighs out 0.0544 g of acrylic acid (HCH,CHCO,) into a 250. mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1900 M NAOH solution. Calculate the volume of NAOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits. mL x10 18 Ar Explanation Check © 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use I Privacy Accessibility 7:37 PM ») ENG 2/27/2021 P Type here to search DELL PrtScr Insert Home End Delet Esc F8 F9 F10 F11 F12 F1 F2 F3 F4 F5 F6 F7 # 24 & Back 2 ĭ 3 ř 4{5 0 6 7 7 Y 8 A 9 q o

Solubility is the concentration of a saturated solution at a specific a) amount b) pressure c) tempature d) volume. It is the measure of how many a) mililiters b) grams of solute are dissolved in 100 mL of solution.

If 0.500 mL of an 0.219 M NaCl solution is added to 100.0 mL of pure water.  what is the concentration of the new solution? Your answer should have 3 sig figs

If 0.500 mL of an 0.208 M NaCl solution is added to 100.0 mL of pure water.  what is the concentration of the new solution? Your answer should have 3 sig figs

If 0.500 mL of an 0.22 M NaCl solution is added to 100.0 mL of pure water. what is the concentration of the new solution? Your answer should have 3 sig figs

1) Get two medium test tubes. Into one, place about 2 mL of a solution of copper (II) sulfate. Into the other add about 2 mL of a solution of sodium phosphate. Note the appearence of the two solutions and then mix them together noting any changes that have taken place.  -Changes that take place -Balanced chemical equation -Balanced ionic equation -balanced net ionic equation

A 20.0 mL solution of NaOH is neutralized with 31.1 mL of 0.200 M HBr. What is the concentration of the original NaOH solution?