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If 0.25 L of a 5.3 M HNO3 solution is diluted to 2.0 L, what is the molarity of the new solution?

If 0.25 L of a 5.3 M HNO3 solution is diluted to 2.0 L, what is the molarity of the new solution?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Diluting a Solution: Calculating Molarity **Problem Statement:** If 0.25 L of a 5.3 M HNO₃ solution is diluted to 2.0 L, what is the molarity of the new solution? **Solution:** To find the molarity of the new solution after dilution, you can use the dilution formula: \[ C_1V_1 = C_2V_2 \] Where: - \( C_1 \) = initial concentration (molarity) = 5.3 M - \( V_1 \) = initial volume = 0.25 L - \( C_2 \) = final concentration (molarity) - \( V_2 \) = final volume = 2.0 L **Calculation:** Rearrange the dilution formula to solve for \( C_2 \): \[ C_2 = \frac{C_1 \times V_1}{V_2} \] Substitute the known values: \[ C_2 = \frac{5.3 \, \text{M} \times 0.25 \, \text{L}}{2.0 \, \text{L}} \] \[ C_2 = \frac{1.325}{2.0} \] \[ C_2 = 0.6625 \, \text{M} \] **Result:** The molarity of the new, diluted solution is \( 0.6625 \, \text{M} \).
Transcribed Image Text:### Diluting a Solution: Calculating Molarity **Problem Statement:** If 0.25 L of a 5.3 M HNO₃ solution is diluted to 2.0 L, what is the molarity of the new solution? **Solution:** To find the molarity of the new solution after dilution, you can use the dilution formula: \[ C_1V_1 = C_2V_2 \] Where: - \( C_1 \) = initial concentration (molarity) = 5.3 M - \( V_1 \) = initial volume = 0.25 L - \( C_2 \) = final concentration (molarity) - \( V_2 \) = final volume = 2.0 L **Calculation:** Rearrange the dilution formula to solve for \( C_2 \): \[ C_2 = \frac{C_1 \times V_1}{V_2} \] Substitute the known values: \[ C_2 = \frac{5.3 \, \text{M} \times 0.25 \, \text{L}}{2.0 \, \text{L}} \] \[ C_2 = \frac{1.325}{2.0} \] \[ C_2 = 0.6625 \, \text{M} \] **Result:** The molarity of the new, diluted solution is \( 0.6625 \, \text{M} \).
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