College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Identify the means by which you can use a converging lens to form a virtual image.
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- For a given converging lens, an object placed 1.15 m away from the lens produces an image 0.28 m away from the lens. What will be the magnification of this object?arrow_forwardA converging lens with a focal length of 12.0 cm forms a virtual image 8.00 mm tall, 17.0 cm to the right of the lens. Determine the position and size of the object. Is the image erect or inverted? Are the object and image on the same side or opposite sides of the lens? Draw a principal-ray diagram for this situation.arrow_forwardIn order to read his book, Stephen uses a pair of reading glasses. When he holds the book at a distance of 22.7 cm from his eyes, the glasses form an upright image a distance of 49.9 cm from his eyes. The distance between the glasses and Stephen's eyes is negligible. What is the magnification of the lens? What is the focl length of the lens? Which of the following statements about the image and the lens is correct? Check All That Apply: The lens is converging. The lens is converging. The image is virtual. The image is virtual. The image is real. The image is real. The lens is divergingarrow_forward
- 10a: Please help answer this ASAParrow_forward4b. A converging lens (fi= 30.0 cm) is placed at a distance of 50.0 cm from a diverging lens a lens (f₂=-30.0 cm) shown in the figure. The combination forms a final image at distance 50.0 cm behind the diverging lens. (a) Where is the first object located? (b) Draw a ray diagram to indicate all the positions of the objects and images for both lenses.arrow_forwardThin lenses. Object O stands on the central axis of a thin symmetric lens. For this situation, each problem in the table (below) gives object distance p (centimeters), the type of lens (C stands for converging and D for diverging), and then the distance (centimeters, without proper sign) between a focal point and the lens. Find (a) the image distance i and (b) the lateral magnification m of the object, including signs. Also, determine whether the image is (c) real or virtual, (d) inverted from object O or noninverted, and (e) on the same side of the lens as object O or on the opposite side. р Lens +8.6 D, 22 (a) (b) (c) (d) (e) i m R/V I/NI Sidearrow_forward
- Thin lenses. Object O stands on the central axis of a thin symmetric lens. For this situation, each problem in the table (below) gives object distance p (centimeters), the type of lens (C stands for converging and D for diverging), and then the distance (centimeters, without proper sign) between a focal point and the lens. Find (a) the image distance i and (b) the lateral magnification m of the object, including signs. Also, determine whether the image is (c) real or virtual, (d) inverted from object O or noninverted, and (e) on the same side of the lens as object O or on the opposite side. (a) (b) (c) (d) (e) Lens i m R/V I/NI Side +54 C, 36 (a) Number i Units (b) Number Units (c) (d) (e) T.... > > >arrow_forwardUnder what conditions a diverging lens will produce a real image? Group of answer choices with a real object closer than the focal length with a virtual object closer than the focal length with a virtual object farther than the focal length neverarrow_forwardAn object is placed in front of a converging lens in such a position that the lens (f = 13.8 cm) produces a real image located 19.8 cm from the lens. Then, with the object remaining in place, the lens is replaced with another converging lens (f = 17.7 cm). A new, real image is formed. What is the image distance of this new image?arrow_forward
- A converging lens (f₁ = 24.0 cm) is located 56.0 cm to the left of a diverging lens (f2 = -28.0 cm). An object is placed to the left of the converging lens, and the final image produced by the two-lens combination lies 20.9 cm to the left of the diverging lens. How far is the object from the converging lens? do1 = iarrow_forwarda) You are holding a convex lens at arm's length and looking at a distant street-light. You observe the up-side down image of the street light to be on your side of the lens and 60.0 mm from the lens. You then train the lens on your study lamp. If your study lamp is 100.0 mm from the lens, how far will the image of the lamp be from the lens (in mm)? b)If your study lamp bulb is spherical of diameter 27.0 mm, what will be the diameter of its image (in mm)?arrow_forwardIf a single lens forms a virtual image of an object, then Group of answer choices The image must be inverted. The lens could be either a diverging or a converging lens. The lens must be a diverging lens. The lens must be a converging lens.arrow_forward
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