b. A smoker detector system uses two devices. CS200 and WS500. If the smoke is present, the probabilitythat it will be detected by device CS200 is 0.75; and by device WS500 is 0.84; and if the smoke isdetected by device CS200 the probability that it is detected by device WS500 is 0.92.Find the probability thatI. The smoke will not be detected by device CS200 given that it has detected by device WS500.II. The smoke will be undetectedIII. The smoke will be detected by at least two devices.

HERE DEFINE EVENTS FROM GIVEN INFORMATION SMOKE will be detected by device CS200 = A smoke will be…

Answered: I. The smoke will not be detected by…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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A researcher thinks some social media sites are more prone to narcissistic behavior (excessive posting) than others. To examine the relationship between narcissism and social media, she recruits users of three different social media sites (Facebook, Twitter and Instagram), follows them for 24 hours and records the number of posts made by each user. The number of posts is given in the table below. Twitter Facebook Instagram 10 7 14 10 8. 10 10 10 11 9. www. 12 wwww. 11 13 12 8. 7 8. 11 8 10 12 11 11 a. Perform a complete hypothesis test to determine whether there are any significant differences among the three groups. Test at the .05 level of significance. SHOW ALL YOUR WORK b. Do you need to perform post hocs? Explain but do not compute the post hocs. C. Compute effect size. d. Summarize your findings in a source table. e. Write an interpretation of our results in APA-format (include means and SDs in your interpretation)
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1. Report the answer with the correct number of significant figures: a b C d e |f 6.0 g Ih li lj 1.4 +2.35 = 7.635 +2.34 = 13.627 -1 = 11.681 3.2 = 14.40 +2.6 - 7.211 = 13.60*3= |27.1*3.47 = 69.3 / 2.467 = 47.321/5.7 = 72.367/8.34 * 2.1 =

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I. The smoke will not be detected by device CS200 given that it has detected by device WS500. II. The smoke will be undetected III. The smoke will be detected by at least two devices.