I. Problem Solving: Solve the following problems completely. Show your complete solution and Sketch the graph. 1. The block on the incline in the given figure shown below is acted upon by a force P inclined at 24° with the horizontal. If force P is resolved into components parallel and perpendicular to the incline and the value of the perpendicular component is 400 N, compute the value of the parallel component and the force P. Find the horizontal and vertical components of force P. Figure:

International Edition---engineering Mechanics: Statics, 4th Edition
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Chapter6: Beams And Cables
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Problem 6.6P: Find the internal force systems acting on sections 1 and 2.
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I. Problem Solving: Solve the following problems completely. Show your complete solution
and Sketch the graph.
1. The block on the incline in the given figure shown below is acted upon by a force P inclined at
24° with the horizontal. If force P is resolved into components parallel and perpendicular to the
incline and the value of the perpendicular component is 400 N, compute the value of the parallel
component and the force P. Find the horizontal and vertical components of force P.
Figure:
P.
2. From the figure, Force F is directed at an angle 0 from + x - axis and the 250 KN force is acting
at a slope of 5:12.
Figure:
+x-аxis
12
250 KN
a. Find the Force F and L0 if the resultant is 400 KN upward to the right with a slope of 3
horizontal to 4 vertical. Use only the given slope in the computation.
b. Find Force F and L0 with the +x- axis if the resultant is zero.
3. A second force (F2) of magnitude 120 N is directed West and a third force (F,) of magnitude 220
N is directed 60° North of East. Find the magnitude and direction of the first force (F1) that
when added, gives a resultant R whose magnitude is 170 N and points 30° North of East.
Transcribed Image Text:I. Problem Solving: Solve the following problems completely. Show your complete solution and Sketch the graph. 1. The block on the incline in the given figure shown below is acted upon by a force P inclined at 24° with the horizontal. If force P is resolved into components parallel and perpendicular to the incline and the value of the perpendicular component is 400 N, compute the value of the parallel component and the force P. Find the horizontal and vertical components of force P. Figure: P. 2. From the figure, Force F is directed at an angle 0 from + x - axis and the 250 KN force is acting at a slope of 5:12. Figure: +x-аxis 12 250 KN a. Find the Force F and L0 if the resultant is 400 KN upward to the right with a slope of 3 horizontal to 4 vertical. Use only the given slope in the computation. b. Find Force F and L0 with the +x- axis if the resultant is zero. 3. A second force (F2) of magnitude 120 N is directed West and a third force (F,) of magnitude 220 N is directed 60° North of East. Find the magnitude and direction of the first force (F1) that when added, gives a resultant R whose magnitude is 170 N and points 30° North of East.
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