I. A steel rod is acted upon by the loading shown below. 50 mm² is the area of the circular rod. The coupling sizes at B, C, and Dare neglected. Use E st = 200 GPa. 1 m -- 1.5 m 1.25 m - A 9 kN B C 4 kN D 2 kN Solve for the following: a) Force in segment AB, PAB b) Force in segment BC, Pác =. c) Force in segment CD, PcD d) Total deformation in the assembly, 8 = kN , (insert type of force here) kN, (insert type of force here) kN, (insert type of force here) %3D mm

Solve fast with suitable diagram

The wooden frame is constructed from wooden 2” X 4” Lumber (Nominal size; Actual size:  1 ½” X 3 ½”) and bears a uniform distributed load. All connections are pin connected. If wo =  100 lb/ft, and L =  9 ft.  Note that the distributed load is the force per unit length in the horizontal direction. A) Find the vertical reaction force at A. 747 450 248 900 563 B) Find the normal stress perpendicular to the grain at point D.  -26.4 -33.9 -85.7 -21.4 -66.9 C) Find the shear force, V, on the cross-section at E. 106 900 159 150 35

a) Draw the free-body diagrams of pulley C and of block E separately. b) Calculate the following: gridinion! the magnitude of tension forces along cables CAD and ACB, Slugmo the mass of block E, ME, mont • and the spring constant, k. patinlog.431 93 80 anil Juods insmo m (SA 1.5 ft 1 ft U D 50° 2 ft beniamos terb salsa binowB 35° C E am Sta Juoma 100.0 8.0 T.0 mao ISTOG ed oj