nt Fortran: What do these Fortran code lines mean? integer :: num read(50,300)num

Name: Ancient Fortran: What do these Fortran code lines mean?integer :: numr
Uploaded: 2024-03-20T06:51:23.000Z
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Description: Ancient Fortran: What do these Fortran code lines mean?integer :: numread(50,300)num

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Ancient Fortran: What do these Fortran code lines mean?

integer :: num

read(50,300)num

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Answer 22

Follow-up Questions

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Follow-up Question

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

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Answer 23

Read through expert solutions to related follow-up questions below.

Follow-up Question

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

Solution

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Answer 24

Read through expert solutions to related follow-up questions below.

Answer 25

Follow-up Question

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

Solution

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SEE SOLUTION

Answer 26

Follow-up Question

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

Solution

by Bartleby Expert

SEE SOLUTION

Answer 27

Follow-up Question

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

Answer 28

Follow-up Question

Answer 29

Follow-up Question

Answer 30

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

Answer 31

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

Answer 32

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Answer 33

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Answer 34

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Answer 37

Follow-up Questions

Read through expert solutions to related follow-up questions below.

Follow-up Question

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

Solution

by Bartleby Expert

SEE SOLUTION

Answer 38

Read through expert solutions to related follow-up questions below.

Follow-up Question

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

Solution

by Bartleby Expert

SEE SOLUTION

Answer 39

Read through expert solutions to related follow-up questions below.

Answer 40

Follow-up Question

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

Solution

by Bartleby Expert

SEE SOLUTION

Answer 41

Follow-up Question

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

Solution

by Bartleby Expert

SEE SOLUTION

Answer 42

Follow-up Question

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

Answer 43

Follow-up Question

Answer 44

Follow-up Question

Answer 45

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

Answer 46

I thought that read(50,300)num means read(50,300)*num or am I wrong? So read(50,300) gets stored in num like :

num = read(50,300) in most languages?

Answer 47

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Answer 48

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Answer 49

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nt Fortran: What do these Fortran code lines mean? integer :: num read(50,300)num

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