Trigonometry (11th Edition)
Trigonometry (11th Edition)
11th Edition
ISBN: 9780134217437
Author: Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher: PEARSON
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I need to know how I get 65 degrees out of sin(.909) because sin of (.909)=.79 and sin^-1=1.14 and I do not have arcsin on my calculator 

9:38
AB =c = 12 ; AC =b; BC= a = 5
Applying pythagorous theorem in the given right
angle triangle
(Hypotenuse)? = (Base)2 + (Perpendicular)?
c2 = a² + b²
122 = 52 + b²
b2 = 144 -25 = 119
%3D
%3D
then b = V119
Step2
b)
According to the given figure
sinB = Perpendicular / Hypotenuse
= b/c
= V119/12
So,
sinB = V119/ 12
= 10.90/12 = 0.9090
%3D
B= sin'(0.9090) = 65.36º
Answer
%3D
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Transcribed Image Text:9:38 AB =c = 12 ; AC =b; BC= a = 5 Applying pythagorous theorem in the given right angle triangle (Hypotenuse)? = (Base)2 + (Perpendicular)? c2 = a² + b² 122 = 52 + b² b2 = 144 -25 = 119 %3D %3D then b = V119 Step2 b) According to the given figure sinB = Perpendicular / Hypotenuse = b/c = V119/12 So, sinB = V119/ 12 = 10.90/12 = 0.9090 %3D B= sin'(0.9090) = 65.36º Answer %3D
10:13
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Math / Trigonometry / Q&A Library / The Sin^-1(.9090) does ..
The Sin^-1(.9090) does not equal to 65 de...
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Expert Answer
Step 1
To find
arcsin(.9090)
Step 2
arcsin(.9090) = 65.36°
It is correct
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Transcribed Image Text:10:13 AA A bartleby.com Upen in the Bartieby app = bartleby Q&A Math / Trigonometry / Q&A Library / The Sin^-1(.9090) does .. The Sin^-1(.9090) does not equal to 65 de... Get live help whenever you Try bartleby -> tutor today need from online tutors! Expert Answer Step 1 To find arcsin(.9090) Step 2 arcsin(.9090) = 65.36° It is correct Was this solution helpful? Privacy - Terms
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