I need help creating a Java code where when the user types 2 the program would just show the number of throws it took. The rest of the Java code is fine but I can't input the elseif when the user types 2 Output is when the user types 2 when the program prints to "Just print the answer" Java code: import java.util.Scanner; public class Dice_Face_In_a_row_FallProject_2 { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int diceFaceNumber, numTimes, numThrows; char choice; do { System.out.println(" This game throws a dice until a particular dice face number"); System.out.println(" appears in a row a certain number of times."); System.out.println("Please enter the version you want:"); System.out.println(" 1) Trace the game."); System.out.println(" 2) Just give the answer"); System.out.println("Please enter 1 or 2"); Scanner input = new Scanner(System.in); int a = input.nextInt(); if (a == 1) { System.out.println("Please enter the dice face number you would like to be repeated. "); diceFaceNumber = input.nextInt(); System.out.println("How many times you want that die face number to appear in a row? : "); numTimes = input.nextInt(); computeNumThrows(diceFaceNumber, numTimes); } else (a == 2){ int numThrows = 0; int count = 0; while (count < numTimes) { int die = (int)(Math.random() * 6) + 1; numThrows++; System.out.println("Please enter the dice face number you would like to be repeated. "); diceFaceNumber = input.nextInt(); System.out.println("How many times you want that die face number to appear in a row? : "); numTimes = input.nextInt(); } System.out.println("Would you like to play the game again? "); System.out.println("Please enter Y for yes or N for no)"); choice = scanner.next().charAt(0); } while (choice == 'Y'); } private static void computeNumThrows(int diceFaceNumber, int numTimes) { int numThrows = 0; int count = 0; while (count < numTimes) { int die = (int)(Math.random() * 6) + 1; numThrows++; System.out.println("you got a " + die); if (die == diceFaceNumber) { count++; System.out.println("Number of times in a row so far is " + count); System.out.println("Number of throws is " + numThrows); } else { int c = 0; System.out.println("Number of times in a row so far is " + c); System.out.println("Number of throws is " + numThrows); } } } }

I need help creating a Java code where when the user types 2 the program would just show the number of throws it took. The rest of the Java code is fine but I can't input the elseif when the user types 2 Output is when the user types 2 when the program prints to "Just print the answer" Java code: import java.util.Scanner; public class Dice_Face_In_a_row_FallProject_2 { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int diceFaceNumber, numTimes, numThrows; char choice; do { System.out.println(" This game throws a dice until a particular dice face number"); System.out.println(" appears in a row a certain number of times."); System.out.println("Please enter the version you want:"); System.out.println(" 1) Trace the game."); System.out.println(" 2) Just give the answer"); System.out.println("Please enter 1 or 2"); Scanner input = new Scanner(System.in); int a = input.nextInt(); if (a == 1) { System.out.println("Please enter the dice face number you would like to be repeated. "); diceFaceNumber = input.nextInt(); System.out.println("How many times you want that die face number to appear in a row? : "); numTimes = input.nextInt(); computeNumThrows(diceFaceNumber, numTimes); } else (a == 2){ int numThrows = 0; int count = 0; while (count < numTimes) { int die = (int)(Math.random() * 6) + 1; numThrows++; System.out.println("Please enter the dice face number you would like to be repeated. "); diceFaceNumber = input.nextInt(); System.out.println("How many times you want that die face number to appear in a row? : "); numTimes = input.nextInt(); } System.out.println("Would you like to play the game again? "); System.out.println("Please enter Y for yes or N for no)"); choice = scanner.next().charAt(0); } while (choice == 'Y'); } private static void computeNumThrows(int diceFaceNumber, int numTimes) { int numThrows = 0; int count = 0; while (count < numTimes) { int die = (int)(Math.random() * 6) + 1; numThrows++; System.out.println("you got a " + die); if (die == diceFaceNumber) { count++; System.out.println("Number of times in a row so far is " + count); System.out.println("Number of throws is " + numThrows); } else { int c = 0; System.out.println("Number of times in a row so far is " + c); System.out.println("Number of throws is " + numThrows); } } } }

Operations Research : Applications and Algorithms

4th Edition

ISBN:9780534380588

Author:Wayne L. Winston

Publisher:Wayne L. Winston

Chapter19: Probabilistic Dynamic Programming

Section: Chapter Questions

Problem 5RP

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Question

Output is when the user types 2 when the program prints to "Just print the answer"

Java code:

import java.util.Scanner;
public class Dice_Face_In_a_row_FallProject_2 {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int diceFaceNumber, numTimes, numThrows;
char choice;

do {
System.out.println(" This game throws a dice until a particular dice face number");
System.out.println(" appears in a row a certain number of times.");
System.out.println("Please enter the version you want:");
System.out.println(" 1) Trace the game.");
System.out.println(" 2) Just give the answer");
System.out.println("Please enter 1 or 2");
Scanner input = new Scanner(System.in);
int a = input.nextInt();
if (a == 1) {
System.out.println("Please enter the dice face number you would like to be repeated. ");
diceFaceNumber = input.nextInt();
System.out.println("How many times you want that die face number to appear in a row? : ");
numTimes = input.nextInt();
computeNumThrows(diceFaceNumber, numTimes);
}
else (a == 2){
int numThrows = 0;
int count = 0;
while (count < numTimes) {
int die = (int)(Math.random() * 6) + 1;

numThrows++;

System.out.println("Please enter the dice face number you would like to be repeated. ");
diceFaceNumber = input.nextInt();
System.out.println("How many times you want that die face number to appear in a row? : ");
numTimes = input.nextInt();

}
System.out.println("Would you like to play the game again? ");
System.out.println("Please enter Y for yes or N for no)");

choice = scanner.next().charAt(0);
} while (choice == 'Y');
}

private static void computeNumThrows(int diceFaceNumber, int numTimes) {
int numThrows = 0;
int count = 0;
while (count < numTimes) {
int die = (int)(Math.random() * 6) + 1;
numThrows++;
System.out.println("you got a " + die);
if (die == diceFaceNumber) {
count++;
System.out.println("Number of times in a row so far is " + count);
System.out.println("Number of throws is " + numThrows);
} else {
int c = 0;
System.out.println("Number of times in a row so far is " + c);
System.out.println("Number of throws is " + numThrows);
}
}
}
}

2
4
Please enter the version you want:
1) Trace the game.
2) Just give the answer.
Please enter 1 or 2
Please enter the dice face number that you would like to be repeated.
Please enter the number of times that you would like 4 to appear in a row.
10
It took 35,698,830 throws to get the number 4 to appear 10 times in a row.
yes
Would you like to play the game again?
Please enter (yes/no)

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