I have rephrased the question to allow for better comprehension so that you can better help me. Using the slope and deflection method: Calculate the value of the end moments E= 200GN/m^2, if a rolled steel joist 560mm ×180mm (I =700×10^(-6) m^4) is used as a beam of 7.2 m effective span with the ends being partially fixed. The loading consists of a point load of 160 KN at the centre of the span and a uniformly distributed load of 60KN which includes the weight of the beam itself. The rigidity of the end connections is such that the slope at the ends is 4 M× 10^(-8) where M is the end moment in Nm. End moments
I have rephrased the question to allow for better comprehension so that you can better help me. Using the slope and deflection method: Calculate the value of the end moments E= 200GN/m^2, if a rolled steel joist 560mm ×180mm (I =700×10^(-6) m^4) is used as a beam of 7.2 m effective span with the ends being partially fixed. The loading consists of a point load of 160 KN at the centre of the span and a uniformly distributed load of 60KN which includes the weight of the beam itself. The rigidity of the end connections is such that the slope at the ends is 4 M× 10^(-8) where M is the end moment in Nm. End moments
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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I have rephrased the question to allow for better comprehension so that you can better help me.
Using the slope and deflection method:
Calculate the value of the end moments E= 200GN/m^2, if a rolled steel joist 560mm ×180mm (I =700×10^(-6) m^4) is used as a beam of 7.2 m effective span with the ends being partially fixed. The loading consists of a point load of 160 KN at the centre of the span and a uniformly distributed load of 60KN which includes the weight of the beam itself. The rigidity of the end connections is such that the slope at the ends is 4 M× 10^(-8) where M is the end moment in Nm.
End moments answer given: 70.43 KNm
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