i) Assuming brown eyes (E) are dominant over blue eyes (e), determine the genotypes of all the following individuals. The blue-eyed son of two brown-eyed parents marries a brown eyed woman whose mother was brown eyed and whose father was blue eyed. Their child is blue eyed.
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i) Assuming brown eyes (E) are dominant over blue eyes (e), determine the genotypes of all the following individuals. The blue-eyed son of two brown-eyed parents marries a brown eyed woman whose mother was brown eyed and whose father was blue eyed. Their child is blue eyed.
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- Assuming brown eyes (B) are dominant over blue eyes (b), determine the genotypes of all the following individuals. The blue-eyed son of two brown-eyed parents marries a brown-eyed woman whose mother was brown eyed and whose father was blue eyed. Their child is blue eyed.In addition to the allelic pair determining pattern baldness in man (B,b), consider early baldness to be due to another autosomal allele (E) on a different pair of chromosomes and also dominant in males but recessive in females. The phenotype for ee may be late or nonbaldness depending on sex and the genotype for B, b alleles. Two doubly heterozygous persons marry. What is the phenotype of the male parent? What is the phenotype of the female parent? Give the phenotypic ratio expected among male children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio. Give the phenotypic ratio expected among female children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio.A homozygous recessive allele, aa, is responsible for albinism. Humans can exhibit this phenotype. In each of the following cases, determine the possible genotypes of the mother and father, and of their children: (a) Both parents have normal phenotypes; some of their children are albino and others are unaffected: (b) Both parents are albino and have only albino children: (c) The woman is unaffected, the man is albino, and they have one albino child and three unaffected children: at a busy hospital. The son of the first couple has hemophilia, a recessive, X-linked Two mothers give birth to sor disease. Neither parent from couple #1 has the disease. The second couple has an unaffected son, despite the fact that the father has hemophilia. The two couples challenge the hospital in court, claiming their babies must have beer swapped at birth. You must advise as to whether or not the sons could have been swapped. What would you say? 5. In a dispute over parentage, the mother of a child with…
- In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. What is the genotype of the woman's father? What is the probability that the couple's first child will be a non-freckled, normal visioned girl? What is the probability that the first two children born to the couple will be freckled and colorblind girls?In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. What is the probability that the first child born to the couple will either be a freckled, colorblind boy or a non‑freckled, normal visioned girl or a non-freckled, normal visioned boy? What is the probability that the first four children born to the couple will be freckled and normal visioned girls?The allele for albinism is recessive to the allele for normal skin pigmentation. All individuals who are homozygous for this recessive allele (m) are unable to produce the enzyme needed for melanin production and are referred to as albinos. In the following statements, determine the correct genotypes: An albino male (genotype A) whose parents both have normal skin pigmentation (genotype B) marries a woman who does not have albinism (genotype C). This woman’s father is an albino (genotype D). The married couple has three children, two with normal skin pigmentation (genotype E) and one exhibiting albinism (genotype F)
- Kernel color in wheat is controlled by 2 pairs of genes (AABB). Determine the color of the offspring with the following genotypes: (Note: 4 contributing alleles – red; 3 contributing alleles – medium red; 2 contributing alleles – intermediate red; 1 contributing allele – red; and 0 – white (AAbb x AaBb, AABb x Aabb, aaBb x Aabb, AABb x aabb, AABb x AaBb) Refer to the problem above, a wheat plant producing medium red seed is crossed with another plant producing intermediate red seed. How many individuals will be? Red Medium red Intermediate red Light red WhiteCalico is a coat color found in cats, which is caused by a SEX-LINKED, CODOMINANT allele, where B = black, O = orange, and BO = calico, The following genotypes are possible; Female cats can be black Xx°, orange XOX°, or calico Xºx°, Male cats can be black XDY or orange XY. An orange male and a black female mate. What proportion of their offsprings will black? O 100% O 50% O 25% O 0%A person is heterozygous for the Freckles phenotype (Ff) and also heterozygous for the PTC-tasting phenotype (Tt). This person's genotype for these two traits is represented as FfTt. A) How many unique gametes could be produced by this individual if you consider these two traits? B) List the different allele combinations that could result.
- Kernel color in wheat is controlled by 2 pairs of genes (AABB). Determine the color of the offspring with the following genotypes: (Note: 4 contributing alleles – red; 3 contributing alleles – medium red; 2 contributing alleles – intermediate red; 1 contributing allele – red; and 0 – white (AAbb x AaBb, AABb x Aabb, aaBb x Aabb, AABb x aabb, AABb x AaBb) Show the solution through punnett square. Refer to the problem above, a wheat plant producing medium red seed is crossed with another plant producing intermediate red seed. How many individuals will be?Show the solution through punnett square. Red Medium red Intermediate red Light red WhiteA light-haired man has blood type O, his wife has dark hair and blood type AB, but her father had light hair. Assume dark hair (H) is dominant to light (h). What is the probability they will have a child with dark hair and blood type A? What is the probability they will have a child with light hair and blood type B? What is the total number of phenotypes their children could show?In domestic cats, the allele (L) is a dominant allele for short-hair trait. The recessive allele for long hair is (I). A female cat with a LI genotype has kittens with a male cat with a II genotype. What is the probability that a kitten has short hair? Hint: it may be helpful to draw a Punnett Square.