
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Questions are about Acid-Base equilibrium, please help!!

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4. Determine the pH of a 0.095 mol/L HIO4 solution if the K₂ = 1.29 x 10-²
+
H₂O (l)
HIO4 (aq)
H3O+ (aq)
C
E
10+ (aq)
+
5. Calculate the K, value for the conjugate base of hydrosulfuric acid. The K₂ for H₂S is 9.6 x 10-8
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- A 0.050 M solution of the salt NaA has a pH of 9.00. Determine the [OH] and the pH of a 0.010 M solution of the acid HA. Show your work in the question parts below. Construct an ICE table for the ionization equation described below.. Use the given information to determine the concentration at equilibrium for all reactants and products.. Initial () Change () Equilibrium () 0.050 + x 0.050 + 2x A (aq) 0 0.050- x A (aq) + H₂O(1) HA(aq) + OH(aq) 0.050 - 2x + 0.050 0.100 + x 0.100 + 2x 0.100 0.100 - x H₂O(l) 0.100 - 2x -X (0.050 + x)² = +x (0.050- x)² +2x HA(aq) (0.100 + x)² RESET -2x (0.100 - x)² + OH (aq)arrow_forward21) The acid in vinegar is phosphoric acid hydrochloric acid acetic acid citric acidarrow_forwardGiven the concentration of [OH-} = 1.7 x 10 -9, What is the pOH ?arrow_forward
- Question 16 of 21 Which one of the following represents the molecular equation for the reaction of HNO3 with CSOH? A) CSOH (aq) + HNO3 (aq) → H₂O (1) + CSNO, (aq) B) Cst (aq) + NO3(aq) → CSNO, (s) C) H+ (aq) + OH- (aq) → H₂O (1) D) CSOH (aq) + HNO3 (aq) → H₂O (aq) + CSNO, (s)arrow_forwardIdentifying the major species in weak acid or weak base... The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HCN is a weak acid. acids: 1 mol of NaOH is added to 1.0 L of a 0.7M HCN bases: O solution. other: O 0.3 mol of NaOH is added to acids: 1.0 L of a solution that is bases: O 0.8M in both HCN and NaCN. O other:arrow_forward
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